A = bh
12 = 4 × h [substitute A for 12 and b for h]
12 / 4 = h
3 = h
Therefore, h equals 4.
D: 89 is the prime number.
Answer:
Susan makes 5 fruit cups
each fruit cup has 5 strawberries and 3 kiwis
so the number of strawberries used is - 5 x 5 = 25 strawberries
and the number of kiwis used - 5 x 3 = 15 kiwis
so the total number of fruits - 25 + 15 = 40 fruits
Joanna uses 40 fruits to make 4 fruit cups
each cup she uses 8 strawberries
therefore total number of strawberries she uses - 8x 4 = 32 strawberries
she has 40 fruits in total and 32 of those are strawberries
the rest are kiwis
number of kiwis = 40 -32 = 8
8 kiwis are there and she has to make 4 cups
so for each cup number of kiwis = 8 / 4 = 2
so each cup has 2 kiwis
Step-by-step explanation:
Since ![[0,4]=[0,1]\cup(1,4]](https://tex.z-dn.net/?f=%5B0%2C4%5D%3D%5B0%2C1%5D%5Ccup%281%2C4%5D)
, we can rewrite the integral as
Now there is no ambiguity about the definition of f(t), because in each integral we are integrating a single part of its piecewise definition:
Both integrals are quite immediate: you only need to use the power rule
to get
![\displaystyle \int_0^11-3t^2\;dt = \left[t-t^3\right]_0^1,\quad \int_1^4 2t\; dt = \left[t^2\right]_1^4](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint_0%5E11-3t%5E2%5C%3Bdt%20%3D%20%5Cleft%5Bt-t%5E3%5Cright%5D_0%5E1%2C%5Cquad%20%5Cint_1%5E4%202t%5C%3B%20dt%20%3D%20%5Cleft%5Bt%5E2%5Cright%5D_1%5E4)
Now we only need to evaluate the antiderivatives:
![\left[t-t^3\right]_0^1 = 1-1^3=0,\quad \left[t^2\right]_1^4 = 4^2-1^2=15](https://tex.z-dn.net/?f=%5Cleft%5Bt-t%5E3%5Cright%5D_0%5E1%20%3D%201-1%5E3%3D0%2C%5Cquad%20%5Cleft%5Bt%5E2%5Cright%5D_1%5E4%20%3D%204%5E2-1%5E2%3D15)
So, the final answer is 15.
Answer:
11 calls
Step-by-step explanation:
She has already spent 42 min. Also she wants to talk for 2 min per call. We can change calls on x. So, only 2x min for her calls left.
42 + 2x = 64
2x = 64 - 42
2x= 22
x=11
Answer: 11 calls
