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2 years ago

The value of p (p^2 + p +1) if p =-1

Mathematics

2 answers:

Anastasy [175]2 years ago

6 0

Hey there!

p(p^2 + p + 1)

= -1(-1^2 + (-1) + 1)

= -1(-1^2 - 2 + 1)

= -1(-1^2) - 1(-2) - 1(1)

= 1 + 2 - 1

= 3 - 1

= 2

Therefore, your answer should be: 2

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

faust18 [17]2 years ago

4 0

Answer:

The answer is 1

Step-by-step explanation:

p² + p + 1; p = -1

Now, Put p = - 1

p² + p + 1

(-1)² + (-1) + 1

1 - 1 + 1 = 1

Thus, The answer is 1

-TheUnknownScientist 72

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Answer:

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Step-by-step explanation:

Given expression :

$\frac{-60}{5}$

Choices given :

A) $\frac{60}{-5}$

B) $60\times \frac{1}{5}$

C) $60\times (-\frac{1}{5})$

D) $-60\times (-\frac{1}{5})$

To find the equivalent expression.

We will first evaluate the given expression.

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Evaluating each choice to select the equivalents.

A) $\frac{60}{-5}$

⇒ $-12$ [Quotient of a positive dividend and a negative divisor is always negative]

B) $60\times \frac{1}{5}$

⇒ $\frac{60}{5}$

⇒ $12$

C) $60\times (-\frac{1}{5})$

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⇒ $-12$

D) $-60\times (-\frac{1}{5})$

⇒ $\frac{60}{5}$ [Product of two negatives is always a positive]

⇒ $12$

∴ We see that the choices A and C are equivalent.

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