Answer:
Step-by-step explanation:
x^2 + 7x + 5x + 35
7x : II
5x: III
35: IV
Answer:
The area of the Iris is 4 times greater.
Step-by-step explanation:
Firstly, we have to realize that we cannot solve this problem without knowing the radius of the iris. because from the information given, the radius of the iris could well be the size of the galaxy and contract from width of 4mm to 2mm and we wouldn't know!
The average radius of the iris is 6mm, so we take this value.
Now, initially the width of the iris is 4mm, that means the radius of the pupil is:

Therefore it's area
is:

When the iris contracts to 2mm, the radius of the pupil becomes:

Then it's area is
:

To find how many times greater this final area is than the initial area, we just divide it by the initial area:

This is 4 times greater than the initial area.
The answer would be 168 :)
We know that
in a unit circle the radius is 1
therefore
[Length of a circumference]=2*pi*r------> 2*pi
if 2pi radians in a circle unit has a length of ------------> 2*pi
2pi/3 radians----------------------------> X
X=2pi/3
the answer is 2pi/3
Answer is 10(2k+5)
-----------------------------------
Work Shown:
20k+50 = 10*2k + 10*5
20k+50 = 10(2k+5)
Note how we can distribute the 10 back in to check our work
10(2k+5) = 10(2k)+10(5) = 20k+50
so that confirms we have the right answer
Another thing to notice is that 10 is the largest factor that we can pull out of 20k and 50. The value 10 is the GCF (greatest common factor) of 20 and 50.