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Akimi4 [234]
2 years ago
11

....................................................................

Mathematics
1 answer:
dexar [7]2 years ago
3 0

Answer:

A D

Step-by-step explanation:

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-0.183 as a fraction in the simplest form??
IRISSAK [1]
-0.183 = -0.183 / 1

Numerator = -0.183 × 10 × 10 × 10 = -183
Denominator = 1 × 10 × 10 × 10 = 1000

Numerator / Denominator = -183 / 1000

Our simplified fraction is:

= -183/1000



8 0
3 years ago
Read 2 more answers
SOLVE THIS PROBLEM ASAP PLS
Drupady [299]
6785 - 6496 = 289 units
289 x 13p = 3757p
3757p = £37.57
37.57 + 21.45 = £59.02
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2 years ago
Life Expectancies In a study of the life expectancy of people in a certain geographic region, the mean age at death was years an
Sphinxa [80]

Answer:

The probability that the mean life expectancy of the sample is less than X years is the p-value of Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}, in which \mu is the mean life expectancy, \sigma is the standard deviation and n is the size of the sample.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

We have:

Mean \mu, standard deviation \sigma.

Sample of size n:

This means that the z-score is now, by the Central Limit Theorem:

Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

Find the probability that the mean life expectancy will be less than years.

The probability that the mean life expectancy of the sample is less than X years is the p-value of Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}, in which \mu is the mean life expectancy, \sigma is the standard deviation and n is the size of the sample.

8 0
2 years ago
HELP PLEASE!Write the equation of the line parallel to y = –x + 5 passing through the point (9, –1).
Westkost [7]
Y=-x+8
gradient of the parallel line is the same as the gradient of the line given, which is -1
to find the y-intercept, sub the values (9,-1) into the equation we are finding which is y=-x+c
5 0
3 years ago
Rylan is hiking in Death valley. He starts at an elevation of 250 feet above sea level and hikes to an 2300 above sea level. How
aalyn [17]

Answer:

250+2300=2350

8 0
3 years ago
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