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Mars2501 [29]
3 years ago
5

A

Mathematics
2 answers:
GREYUIT [131]3 years ago
8 0
The answer is D. First, it is the segment addition postulate because the two segments make up the whole. Second, it's substitution because you are substituting EF + FG for FH.

Hope this helps!
jonny [76]3 years ago
8 0

Answer:

d:(1)Segment addition Postulate

(2).Substitution Property of equality.

Step-by-step explanation:

We are given that

EG=FH

We have to write a justification for each step.

1.EG=FH

Given information

2.EG=EF+FG

Segment addition Postulate

3.FH=FG+GH

Segment addition postulate

4.EF+FG=FG+GH

Substitute property of equality

EF=GH

Subtraction property of equality

Answer:d:(1)Segment addition Postulate

(2).Substitution Property of equality.

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The average of 5 quiz grades is 10. When the lowest grade is dropped and the new average is calculated, it turns out to be 11. W
V125BC [204]

Answer:

The score of the dropped grade is 6

Step-by-step explanation:

To find the average of a set of numbers you need to add all the numbers and divide by how many numbers there are. The problem wants you to solve it in reverse. Let put this into an algebraic equation with a, b, c, d, and e being the variables of the test scores

(a+b+c+d+e)/5=10

Then we can multiply both sides by 5 and get

a+b+c+d+e=50

Lets assume that c is the lowest test score. To calculate the average of that we get

a+b+d+e/4=11

Doing the same thing, we know that a+b+d+e=44

Now compare the two:

a+b+c+d+e=50

a+b+d+e=44

We can now know that c=50-44=6

So, 6 is the score of the dropped quiz. Hope that helped!

4 0
3 years ago
The area of a regular octagon is 35 cm squared what is the area of a regular octagon with sides five times as long
KATRIN_1 [288]
The answer would be 875cm squared
7 0
3 years ago
Read 2 more answers
How many cubes with side lengths of cm does it take to fill the prism?
Sophie [7]
The answer is Stan twiceushisnsskkemr
5 0
2 years ago
If P is the incenter of triangle JKL, find the measure of JKP.
ladessa [460]

Answer:

m∠JKP = 31.5°

Step-by-step explanation:

Incenter of a triangle is the point where all the bisectors of interior angles intersect each other.

JN is the angle bisector of ∠KJL.

Therefore, m∠KJN = m∠LJN

(7x - 6) = (5x + 4)

7x - 5x = 6 + 4

2x = 10

x = 5

m∠KJN = (7x - 6)

            = 7(5) - 6

            = 35 - 6

            = 29°

In ΔKJN,

m∠JKN + m∠KNJ + m∠NJK = 180°

m∠JKN + 90° + 29° = 180°

m∠JKN = 180°- 119° = 61°

Since KO is the angle bisector of ∠JKN,

m∠JKP = \frac{1}{2}(\angle JKN)

            = \frac{1}{2}(61)

            = 30.5°

6 0
3 years ago
How do you write 3,246.78 in expanded form using base 10
tankabanditka [31]
3x1000+2x100+4x10+6x1+7x(1/10)+8x(1/100)
5 0
3 years ago
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