Evaluate 4k2 + 3 when k = 5

Mathematics

1 answer:

yan [13]4 years ago

8 0

103 if that's a k squared

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Arwen uses an eye dropper that produces drops that has a volume of 1/8 milliliter to fill 30 milliliter test tube. How many drop

oksian1 [2.3K]

To answer this question, you need to know how many drops go into atheism test tube.

Each drop is 1/8 milliliter. The test tube is 30 milliliter.

So, divide 30 by 1/8 to see how many times 1/8 goes into 30.

30 divided by 1/8 = 30 times 8 = 240

It takes 240 drops (that's a lot!) to fill up the test tube.

Hope this helps!

4 0

4 years ago

I believe the answer is C. however, I'm not 100% sure.

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3 years ago

A dealer paid $10,000 for a boat at an auction. At the dealership, a sales person sold the boat for 30% more than the auction pr

vazorg [7]

30% of 10,000 is 3,000, so the salesperson would have sold the boat for $13,000. The difference between the auction price and dealership price is 3,000. The commission is 25% of 3,000, which is $750.

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3 years ago

Let’s pretend that we want to give our employees in total a28% raise in the next two years, but we want to spread out aconsisten

Roman55 [17]

Solution

- The solution steps are given below:

$\begin{gathered} \text{ Let the original amount be X} \\ \\ \text{ If we want a 28\% raise over the next two years, then it means that the amount will be:} \\ X+\frac{28}{100}X=1.28X \\ \\ \text{ If we want to give them a consistent raise each year, we can compute the scenario as follows:} \\ \text{ Let the percentage be }y \\ \\ X+y\%\text{ of }X=\text{ Salary after first year} \\ \\ (X+y\%\text{ of }X)+y\%\text{ of }(X+y\%\text{ of }X)\text{ = Salary after second year.} \\ \\ \text{ But we already know that the salary after second year is }1.28X \\ \text{ Thus, we can say:} \\ (X+y\%\text{ of }X)+y\%\text{ of }(X+y\%\text{ of }X)=1.28X \\ \\ \text{ Simplifying, we have:} \\ X+\frac{yX}{100}+\frac{y}{100}(X+\frac{yX}{100})=1.28X \\ \\ \text{ Divide through by }X \\ 1+\frac{y}{100}+\frac{y}{100}(1+\frac{y}{100})=1.28 \\ \\ \text{ Subtract 1 from both sides and expand the brackets} \\ \frac{y}{100}+\frac{y}{100}+(\frac{y}{100})^2=1.28-1=0.28 \\ \\ \frac{2y}{100}+(\frac{y}{100})^2=0.28 \\ \\ \text{ Multiply both sides by }100^2 \\ 200y+y^2=2800 \\ \\ \text{ Rewrite, we have:} \\ y^2+200y-2800=0 \\ \\ Solving\text{ the equation using the Quadratic formula, we have that:} \\ y=\frac{-200\pm\sqrt{200^2-4(-2800)}(1)}{2(1)} \\ \\ y=-213.137\text{ or }13.137 \\ \\ \text{ Since the change in salary is an increase, thus, the rate }y\text{ has to be positive.} \\ \text{ Thus, } \\ y=13.137\approx13.14\% \\ \\ \end{gathered}$

Final Answer

y = 13.14%

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