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navik [9.2K]
3 years ago
11

Question 2 (4 points)

Mathematics
1 answer:
Yakvenalex [24]3 years ago
3 0
The answer is a. y=3/4x + 4
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Evaluate 15/5 + 40 . 7 - 3 to the power of 4.
Lina20 [59]
15/5 + 40.7 -3^4
= 3 + 40.7 - 81
= -37.3


hope this helps! :)))
4 0
3 years ago
2(x + 2) + 2 = 2(x + 3) + 1
Maslowich

Answer:

No solution

Step-by-step explanation:

5(x + 4) – x = 4(x + 5) – 1

x = ?

Solution:

5(x+4)−x=4(x+5)−1

Apply Distributive property:

  • (5)(x)+(5)(4)−x=(4)(x)+(4)(5)−1
  • 5x+20−x=4x+20−1

Combine Like Terms:

  • (5x−x)+(20)=(4x)+(20−1)
  • 4x+20=4x+19
  • 4x+20=4x+19

Subtract 4x from both sides:

  • 4x+20−4x=4x+19−4x
  • 20=19

Subtract 20 from both sides:

  • 20−20=19−20
  • 0=−1

There isn't any solutions.

6 0
2 years ago
Como se realiza eso?
amm1812

Answer:

english

Step-by-step explanation:

3 0
3 years ago
3 consecutive integers for 273
a_sh-v [17]

Answer:

90, 91 and 92

Step-by-step explanation:

Given

Consecutive integers = 273

Required

Find the integers

The question seem to be incomplete. However, I'll assume we're dealing with sum.

Let the smallest integer be y.

So,

y + y + 1 + y + 2 = 273

Collect like terms.

y + y + y = 273 - 2 - 1

3y = 270

Divide both sides by 3

y = 90

Hence, the integers are 90, 91 and 92

8 0
3 years ago
A red light
ANEK [815]

Answer:

Both lights would flash together after every 30 seconds.

Step-by-step explanation:

6 = 2 * 3 and 10 = 2 * 5.

LCM (Least Common Multiple) of 6 and 10 = 2 * 3 * 5 = 30.

Therefore, both lights wold flash together after every 30 seconds.

3 0
4 years ago
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