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3 years ago

12

Which pair best represents a causation statement?

1 answer:

grandymaker [24]3 years ago

4 0

Answer:

C. the number f books read and the size of someone's vocabulary

Step-by-step explanation:

causation is the action of causing something, thats the only one that makes sense lol

You might be interested in

If 25 percent of your classmates have cats, and your class has 20 students, how many students have cats? (I have to show my work

Rufina [12.5K]

Answer:

5 students.

Step-by-step explanation:

25% is a quarter of the amount, or 1/4. A quarter of 20 is 5, since 4 times 5 is 20. So 5 students have cats.

5 0

3 years ago

How do you do systems of two equations? Problem: y=-3x+4, y=3x-2

juin [17]

I assume you are trying to solve for each variable. if thats the case you want to use one equation to solve for y and then plug the y value into the next variable
Problem: y =-3x=4 so -3x+4=3x-2
x=1
plug x value into one of the equations
y=3(1)-2
y=1

8 0

3 years ago

I need help ASAP!!!!!!!!! PLZZZ

frutty [35]

Answer:

b

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are equal, that is

$\frac{AB}{XY}$ = $\frac{BC}{YZ}$ , substitute values

$\frac{15}{10}$ = $\frac{21}{YZ}$ ( cross- multiply )

15YZ = 210 ( divide both sides by 15 )

YZ = 14 → b

6 0

3 years ago

: Show that the solution of the differential equation: = − − − − − is of the form: + + ( − ) = + , When = and =

Serhud [2]

Answer:

$y = \tan(x + \frac{x^2}{2})$

Step-by-step explanation:

Poorly formatted question; The complete question requires that we prove that $y=\tan(x+\frac{x\²}{2})$

When

$\frac{dy}{dx} =1+xy\²+x+y\²$ and $y(0)=0$

We have:

$\frac{dy}{dx} =1+xy\²+x+y\²$

Rewrite as:

$\frac{dy}{dx} =1+x+xy\²+y\²$

Factorize

$\frac{dy}{dx} = (1+x)+y\²(x+1)$

Rewrite as:

$\frac{dy}{dx} = (1+x)+y\²(1+x)$

Factor out 1 + x

$\frac{dy}{dx} = (1+y\²)(1+x)$

Multiply both sides by $\frac{dx}{1 + y^2}$

$\frac{dy}{1+y\²} = (1+x)dx$

Integrate both sides

$\int \frac{dy}{1+y\²} = \int (1+x)dx$

Rewrite as:

$\int \frac{1}{1+y\²} dy = \int (1+x)dx$

Integrate the left-hand side

$\int \frac{1}{1+y\²} dy = \tan^{-1}y$

Integrate the right-hand side

$\tan^{-1}y = x + \frac{x^2}{2} + c$

$y(0)=0$ implies that: $(x,y) = (0,0)$

So:

$\tan^{-1}y = x + \frac{x^2}{2} + c$ becomes

$\tan^{-1}(0) = 0 + \frac{0^2}{2} + c$

This gives:

$0 = 0 +0 + c$

$0 =c$

$c = 0$

The equation $\tan^{-1}y = x + \frac{x^2}{2} + c$ becomes

$\tan^{-1}y = x + \frac{x^2}{2} + 0$

$\tan^{-1}y = x + \frac{x^2}{2}$

Take tan of both sides

$y = \tan(x + \frac{x^2}{2})$ --- Proved

8 0

3 years ago

Plants per row<br> 100 plants in 5 rows<br> Unit rate

SCORPION-xisa [38]

Answer:

100 plants/5 rows divided by 5 = 20 plants/1 row. hope this helps

Step-by-step explanation:

- Zombie

7 0

3 years ago

Read 2 more answers