Answer:
x=1
y=s
z=1
Step-by-step explanation:
(x, y, z)=(1, 0, 1)
Substitute 0 for y
Confirming if t=0 satisfy the other equation
x = e^−2t cos 4t = e^−2(0)cos(4*0)
= e^(0)cos(0) = 1
z = e^−2t = e^−2(0) = 0
Therefore t=0 satisfies the other equation
Finding the tangent vector at t=0
The vector equation of the tangent line is
(1, 0, 1) +s(0,1,0)= (1, s, 1)
The parametric equations are:
x=1
y=s
z=1
Answer:
A.
Step-by-step explanation:
We have that, ΔABC is transformed to get ΔA''B''C''.
We see that the following transformations are applied:
1. Reflection across x-axis i.e. flipped across x-axis.
Now, ΔABC is reflected across x-axis along the line AC to get ΔA'B'C'.
2. Translated 2 units down i.e. shifted 2 units down and and then translated 6 units to the left i.e. shifted 6 units to the left.
So, ΔA'B'C' is translated 2 units downwards and 6 units to the left to get ΔA''B''C''.
Hence, the sequence of transformations is Reflection across x-axis and then Translation of 2 units down and 6 units left.