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2 years ago

Solve proportion round it to the nearest hundredth

Mathematics

1 answer:

Sunny_sXe [5.5K]2 years ago

7 0

Answer:

7.7 = 2.3

3.6 b

7.7b= 8.28

7.7 7.7

b = 1.075324675

b = 1.08

A) If the last digit in the fractional part of 1.080 is less than 5, then simply remove the last the digit of the fractional part. With 1.080, rule A applies and 1.08 rounded to the nearest hundredth is:

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Simplify 2√2-√3 --------------- √2+√3

serious [3.7K]

Step-by-step explanation:

$= \frac{2 \sqrt{2} - \sqrt{3} }{ \sqrt{2} + \sqrt{3} }$

$= \frac{2 \sqrt{2} - \sqrt{3} }{ \sqrt{2} + \sqrt{3} } \times \frac{ \sqrt{2} - \sqrt{3} }{ \sqrt{2} - \sqrt{3} }$

$= \frac{ 2( \sqrt{2} - \sqrt{3} )( \sqrt{2} - \sqrt{3} )}{ { \sqrt{2} }^{2} - { \sqrt{3} }^{2} }$

$= \frac{2(2 - \sqrt{6} - \sqrt{6} - 3) }{2 - 3}$

$= \frac{2( - 1 - 2 \sqrt{6} )}{ - 1}$

$= \frac{ - 2(1 + 2 \sqrt{6} )}{ - 1}$

$= 2(1 + 2 \sqrt{6} )$

$= 2 + 4 \sqrt{6}$

6 0

1 year ago

HEY WHAT IS THIS PLEASE HELPPPP 1+20000

Andrei [34K]

Answer:

20001

Step-by-step explanation:

Add 1 to 20000

5 0

3 years ago

Read 2 more answers

You are running a fuel economy study. One of the cars you find is blue. It can travel 41 1/2 miles on 1 1/4 gasoline. Another ca

sashaice [31]

Answer:

Step-by-step explanation:

We want to study the fuel consumption of each car, i.e the amount of mile per gallon the cars will consume

Step one:

given data:

First car

distance covered= 41 1/2 = 41.5miles

amount of gallons= 1 1/4= 1.25gal

the miles per gallons= 41.5/1.25=33.2 miles per gallon

Second car

distance covered= 21 3/5= 21.6miles

amount of gallons=4/5= 0.8gal

the miles per gallons= 21.6/0.8=27 miles per gallon

1. Therefore the unit rate of

the first car = 33.2 miles per gallon

the second car=27 miles per gallon

2. the first car can travel a greater distance on 1 gallon of gasoline

8 0

2 years ago

I need help with #2 and #6 pleaseeeeee

Mumz [18]

Answer:

Area of the rectangle = x² - 3x - 10

2019

Step-by-step explanation:

Length of the rectangle = x + 2

Width of the rectangle = x - 5

Area of the rectangle = length × width

= (x + 2) (x - 5)

= x² + 2x - 5x - 10

= x² - 3x - 10

Area of the rectangle = x² - 3x - 10

C = 20t² + 135t + 3050

Where

C = the number of new cars

t = year the number of new cars was purchased

t = 0 corresponds to 1998

Find the when c = 15,000

C = 20t² + 135t + 3050

15,000 = 20t² + 135t + 3050

20t² + 135t + 3050 - 15,000 = 0

20t² + 135t - 11,950 = 0

4t² + 27t - 2390 = 0

Solve using quadratic equation

t = -b ± √b² - 4ac / 2a

= -27 ± √27² - 4(4)(-2390) / 2(4)

= -27 ± √729 -(-38240) / 8

= -27 ± √729 + 38240 / 8

= -27 ± √38969 / 8

= -27/8 + √38969/8 or 27/8 - √38969/8

= -3.375 + 197.41/8 or -3.375 - 197.41/8

= -3.375 + 24.67625 or -3.375 - 24.67625

t = 21.30125 or - 28.05125

t cannot be negative

Therefore,

t = 21.30125

To the nearest whole number

t = 21

Recall,

t = 0 corresponds to 1998

Therefore

1998 + 21 = 2019

c = 15,000 in the year 2019

4 0

2 years ago

There are 59 people going on a field trip.

laila [671]

The answer to this question is the school is going to have to rent 2 vans extra. The reason is because each van hols 8 people right. for the 6 vans that the school already owns, that will be 48 students in vans. When you subract that from 59, you get 11 students that still need a van, so 11 students can not fit in one extra van so the school would need two. Hope this gives you what you were looking for. God bless, and hope this helped. Also, please let me know if it was correct.

6 0

2 years ago