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Tju [1.3M]
3 years ago
12

Solve proportion round it to the nearest hundredth

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
7 0

Answer:

<u>7</u><u>.</u><u>7</u><u> </u><u> </u>= <u>2</u><u>.</u><u>3</u>

3.6 b

<u>7</u><u>.</u><u>7b</u>= <u>8</u><u>.</u><u>28</u>

7.7 7.7

b = 1.075324675

b = 1.08

A) If the last digit in the fractional part of 1.080 is less than 5, then simply remove the last the digit of the fractional part. With 1.080, rule A applies and 1.08 rounded to the nearest hundredth is:

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What irrational number can be added to pi to get a sum that is rational
m_a_m_a [10]

Answer is  -pi

Let x be this unknown number. Adding on x to pi gets us the expression x+pi

If we set x+pi equal to zero (which is a rational number) and solve for x, we get

x+pi = 0

x+pi - pi = 0 - pi

x = -pi

so adding pi to -pi will lead to 0 since

x+pi = -pi+pi = 0

5 0
4 years ago
I need help in algebra
mash [69]

Answer: No

Step-by-step explanation:

Because there is more than one 3 in the following ordered pair. If you make this a table it will be easier.

4 0
4 years ago
Read 2 more answers
Solve the equation in the complex number system. x^2-12x+40=0
mylen [45]

solving the equation x^2-12x+40=0 we get x=6+2i\,\,and\,\,x=6-2i

Step-by-step explanation:

Solve the equation:

x^2-12x+40=0

We can solve using quadratic Formula:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

a= 1, b = -12, c = 40

Putting values:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-12)\pm\sqrt{(-12)^2-4(1)(40)}}{2(1)}\\x=\frac{12\pm\sqrt{144-160}}{2}\\x=\frac{12\pm\sqrt{-16}}{2}\\We\,\,know\,\,\sqrt{-1}=i\\ x=\frac{12\pm4i}{2}\\ x=\frac{12+4i}{2}\,\,and\,\, x=\frac{12-4i}{2}\\ x=\frac{4(3+i)}{2}\,\,and\,\, x=\frac{4(3-i)}{2}\\x=2(3+i)\,\,and\,\,x=2(3-i)\\x=6+2i\,\,and\,\,x=6-2i

So, solving the equation x^2-12x+40=0 we get x=6+2i\,\,and\,\,x=6-2i

Keywords: Solving quadratic equation

Learn more about Solving quadratic equation at:

  • brainly.com/question/1414350
  • brainly.com/question/1464739
  • brainly.com/question/7361044
  • brainly.com/question/1357167

#learnwithBrainly

5 0
3 years ago
3:5 as a ladder methed​
8090 [49]

Answer:

yes

Step-by-step explanation:

3 0
3 years ago
Need help here plss
Ierofanga [76]

Two linear equations can have no solutions, exactly one solution or infinitely many solutions. There will be no solution if the lines are parallel on a graph. There will be exactly one solution if the lines intersect each other on a single point. And finally, there will be infinite solutions if the lines overlap each other perfectly.

A single line however has infinite ordered pair solutions as the line travels infinitely in both directions on the coordinate plane. For example, using the equation y=3x, for any real value of x, we will get a real value for y.

Linear inequalities with two variables have infinitely many solutions. We can use the inequality y>3x as an example. For any real value of x, we will get a real value for y.

I hope this helps!

6 0
3 years ago
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