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Veseljchak [2.6K]
2 years ago
11

State the y-intercept

Mathematics
2 answers:
schepotkina [342]2 years ago
8 0
(0,3) that is where it crosses the y axis
Nataliya [291]2 years ago
4 0

Answer: (0, 3)

Step-by-step explanation:

Find where 0 is on the x axis and correspond the coordinate to the y axis.

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6.9 I think.

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QUESTION ONE:<br> Solve for h.
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Answer:

h = - 105

Step-by-step explanation:

Given

\frac{h}{14} = - 7.5 ( multiply both sides by 14 to clear the fraction )

h = - 105

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Identify any solutions to the system shown here.
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The answer would be B and D.  This can be found by putting the x and y values into the inequality to find whether or not they are true.

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A real estate agent has 19 properties that she shows. She feels that there is a 30% chance of selling any one property during a
netineya [11]

Answer:

P(X \geq 5)=1-P(X

We can find the individual probabilities:

P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114

P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092

P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358

P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869

P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491

And replacing we got:

P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=19, p=0.3)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

And we want to find this probability:

P(X \geq 5)

And we can use the complement rule:

P(X \geq 5)=1-P(X

We can find the individual probabilities:

P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114

P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092

P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358

P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869

P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491

And replacing we got:

P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178

4 0
3 years ago
2//2/2/3/2/2//3/3/3//3/3/4/5/5​
Wewaii [24]

Answer:  

can u be more specific so i can properly help u  

Explanation:  

pls explain and i will edit my answer  

6 0
3 years ago
Read 2 more answers
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