Answer:
cos(x) = square root 2 over 2; tan(x) = 1
Step-by-step explanation:
![\frac{\sqrt{2} }{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%20%7D%7B2%7D)
was, before it was rationalized,
![\frac{1}{\sqrt{2} }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%20%7D)
Therefore,
![sin(x)=\frac{1}{\sqrt{2} }](https://tex.z-dn.net/?f=sin%28x%29%3D%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%20%7D)
The side opposite the reference angle measures 1, the hypotenuse measures square root 2. That makes the reference angle a 45 degree angle. From there we can determine that the side adjacent to the reference angle also has a measure of 1. Therefore,
and
since tangent is side opposite (1) over side adjacent (1),
tan(x) = 1
Answer: see proof below
<u>Step-by-step explanation:</u>
Use the Double Angle Identity: sin 2Ф = 2sinФ · cosФ
Use the Sum/Difference Identities:
sin(α + β) = sinα · cosβ + cosα · sinβ
cos(α - β) = cosα · cosβ + sinα · sinβ
Use the Unit circle to evaluate: sin45 = cos45 = √2/2
Use the Double Angle Identities: sin2Ф = 2sinФ · cosФ
Use the Pythagorean Identity: cos²Ф + sin²Ф = 1
<u />
<u>Proof LHS → RHS</u>
LHS: 2sin(45 + 2A) · cos(45 - 2A)
Sum/Difference: 2 (sin45·cos2A + cos45·sin2A) (cos45·cos2A + sin45·sin2A)
Unit Circle: 2[(√2/2)cos2A + (√2/2)sin2A][(√2/2)cos2A +(√2/2)·sin2A)]
Expand: 2[(1/2)cos²2A + cos2A·sin2A + (1/2)sin²2A]
Distribute: cos²2A + 2cos2A·sin2A + sin²2A
Pythagorean Identity: 1 + 2cos2A·sin2A
Double Angle: 1 + sin4A
LHS = RHS: 1 + sin4A = 1 + sin4A ![\checkmark](https://tex.z-dn.net/?f=%5Ccheckmark)
Answer: The angle equals 45
∘ and the supplement is 135
∘
Explanation:
Since the supplement is three times the angle, we can say s = 3
a
Since we know the supplement is
180
−
a
, we can plug that in.
180 - a = 3a
180 =
4
a (add a to both sides)
45 = a (divide both sides by 4)
Since we know the angle now, all we have to do is multiply it times 3 to find the supplement.
45 × 3 = 135