What is the eighth term in the geometric series 1250

In the year 2000, the average cost of a computer could be modeled by the equation C = -5t2 + 750, where t is the number of years

elena55 [62]

Answer:

$\Delta C=-5t^2-250$

Step-by-step explanation:

Given:

The average cost of a computer in the year 2000 is given as:

$C=-5t^2+750$

The average cost of a computer in the year 2008 is given as:

$C=-10t^2+500$

Now, the difference in average cost between the years 2008 and 2000 can be calculated by subtracting the average cost in 2000 from the average cost in 2008.

Framing in equation form, we get:

Difference in average cost (ΔC) is given as:

$\Delta C=C_{2008}-C_{2000}\\\\\Delta C= (-10t^2+500)-(-5t^2+750)\\\\\textrm{Distributing the megative sign inside the second polynomial, we get:}\\\\\Delta C=-10t^2+500+5t^2-750\\\\\textrm{Grouping like terms, we get}\\\\\Delta C=(-10t^2+5t^2)+(500-750)\\\\\Delta C=-5t^2-250$

Therefore, the difference in the costs for a computer between 2008 and 2000 is $\Delta C=-5t^2-250$

7 0

3 years ago

Suppose the true proportion of students at a college who study abroad is 0.25. I select a random sample of 40 students from the

Julli [10]

Answer:

$\mu_{\hat p} = 0.25$

$\sigma_{\hat p}= \sqrt{\frac{0.25*(1-0.25)}{40}}= 0.0685$

$z = \frac{0.2-0.25}{0.0685}= -0.730$

And we can use the normal standard distribution or excel to find this probability and we got:

$P(\hat p$

Step-by-step explanation:

We define the parameter as the proportion of students at a college who study abroad and this value is known $p =0.25$ , we select a sample size of n =40 and we are interested in the probability associated to the sample proportion, but we know that the distirbution for the sample proportion is given by:

$\hat p \sim N(p , \sqrt{\frac{p(1-p)}{n}}$

And the paramters for this case are:

$\mu_{\hat p} = 0.25$

$\sigma_{\hat p}= \sqrt{\frac{0.25*(1-0.25)}{40}}= 0.0685$

We want to find the following probability:

$P(\hat p< 0.2)$

For this case since we know the distribution for the sample proportion we can use the z score formula given by:

$z = \frac{\hat p -\mu_{\hat p}}{\sigma_{\hat p}}$

Replacing the info given we got:

$z = \frac{0.2-0.25}{0.0685}= -0.730$

And we can use the normal standard distribution or excel to find this probability and we got:

$P(\hat p$

8 0

3 years ago

Which statement correctly explains how Mari could find the solution to the following system of linear equations using

just olya [345]

Multiply the first equation by 7 and the second equation by 2, and then add.

Step-by-step explanation:

2f - 5g=-9

-7f + 3g=4

To eliminate any variable , we need to make the coefficients same with different sign and add it

the coefficient of 'f' in first equation is 2

the coefficient of 'f' in second equation is -7

We already have different sign so we make the coefficients same

To make the coefficient same , we multiply the first equation by 7 and second equation by 2

So equation becomes

14f - 35g = -63

-14f + 6g = 8

Now when we add both equations, 'f' gets cancelled

-29g = -55

7 0

3 years ago

Rewrite as an addition problem:<br> (5w +6u) - (4w - 3u)

stepladder [879]

Answer:

(5w+ 6u ) + (-4w +3u)

Step-by-step explanation:

(5w+ 6u ) + (-4w +3u)

this can be done by multiplying all in the second parentheses by -1.

6 0

3 years ago

I have a math question that im stuck on 2 - 2x ≥ x + 66

kakasveta [241]

Answer:

x is less than or equal to 64/-3

8 0

3 years ago

What is the eighth term in the geometric series 1250 – 250 + 50 - …?​

What is the eighth term in the geometric series 1250 – 250 + 50 - …?