14/99
Select 1 marble; the chance that it is white is 4/12. Select a 2nd marble; the chance that it is white is 3/11. Select a 3rd; the chance it is white is 2/10. Select a 4th; the chance it is red is 8/9. Select a 5th; the chance it is red is 7/8. The chance of getting this specific set of 5 marbles in this order is (4/12)×(3/11)×(2/10)×(8/9)×(7/8)=(2×7)/(11×10×9).
This specific set could occur in the permutation of 5 things taken 5 at a time where 3 are identical (white), and the other 2 are also identical (red). The formula for this is 5!/(3!2!)=10.
Combining the chance of getting white, white, white, red, red with the number of ways 3 white and 2 red could have been distributed in the draw of 5 marbles gives the answer:
{(2×7)/(11×10×9)}×10=14/99
A similar process will show that the chance of getting 5 red marbles is 7/99; 4 white and 1 red is 1/99; 2 white and 3 red is 42/99; and 1 white and 4 red is 35/99.
Answer:
x ≥ 6 or x ≤ -2
Step-by-step explanation:
- I x - 2 I + 4 ≤ 0
- I x - 2 I ≤ -4
I x - 2 I ≥ 4
x - 2 ≥ 4 or x - 2 ≤ -4
x ≥ 6 or x ≤ -2
9514 1404 393
Answer:
-31/15
Step-by-step explanation:
Put the numbers in the expression and do the arithmetic.
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Your graphing calculator can probably help with this.
Answer:
assume the formula is true for n is equal to k prove that result is true for n is equal to k + 1 hence result proves since the thorum is true for n is equal to 1 and n k + 1 is unit through a and
The subtraction sign in front of the second set of parenthesis changes the signs on the terms inside those parenthesis. So this could be rewritten as
. None of the exponents on the x are the same, so we will just express it in terms of descending powers of x.
. This is also the same as
if you don't like to start with a negative. Either one is correct.
