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iris [78.8K]
3 years ago
13

I have 8 boxes of chocolate i eat 3 chocolates from each box i now have 72 chocolates in total

Mathematics
2 answers:
nydimaria [60]3 years ago
8 0

Answer: there were 12 chocolates in each box. (Originally, before any got eaten)

Step-by-step explanation: let x represent the total amount of chocolates in each box.

8x - 3(8) = 72

8x - 24 = 72 add 24 to both sides

8x = 96 divide both sides by 8

X = 12

AfilCa [17]3 years ago
5 0

Answer:

That means you had 48 chocolates in each box

Step-by-step explanation:

Since you eat 3 chocolates from all 8 boxes, you do this:

8 x 3 which = 24

Now since you have 72 chocolates left you do this:

72 - 24 which = 48

So, therefore, there were originally 48 chocolates in each box

(Don't eat so much chocolate lol you could get sick)

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You are given an original figure with coordinates B(-7,-2), A(5,-2), and D(-7,7) and its image with coordinates J(-3,0), K(1,0),
MAVERICK [17]

Answer:

see below

Step-by-step explanation:

DB = 9  units  (by counting)

BA = 12 units  (by counting)

DA  can be found by using the pythagorean theorem

a^2 +b^2 = c^2

BD^2 + BA^2 = DA ^2

9^2 +12^2 = DA^2

81 +144 = DA^2

225 = DA ^2

Take the square root of each side

sqrt(225) = sqrt(DA^2)

15 = DA

LJ = 3  units  (by counting)

JK = 4 units  (by counting)

LK  can be found by using the pythagorean theorem

a^2 +b^2 = c^2

LJ^2 + JK^2 = LK ^2

3^2 +4^2 = LK^2

9 +116 = LK^2

25 = LK ^2

Take the square root of each side

sqrt(25) = sqrt(LK^2)

5 = LK

Scale factor from BAD to JKL

15 to 5

Divide each side by 5

3 to 1

We multiply by 1/3 to go from the big to small

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3 years ago
An airplane is flying at an altitude of 6000 m over the ocean directly towards a coastline. At A certain time the angle of depre
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If $9x^2 - 16x + k$ is a perfect square trinomial, find $k$.
Lady_Fox [76]

Answer:is this a real quistion

Step-by-step explanation:?

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3 years ago
Write an equation for the line shown on the graph.
Irina18 [472]

Answer:

\large\boxed{y=\dfrac{2}{3}x+1}

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept → (0, </em><em>b</em><em>)</em>

<em />

The fromual of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

<em>(x₁, y₁), (x₂, y₂)</em><em> - points on a line</em>

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We have the points from the graph:

(0, 1) → <em>b = 1</em> and (3, 3).

Calculate the slope:

m=\dfrac{3-1}{3-0}=\dfrac{2}{3}

Finally we have the equation of a line:

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3 years ago
The game of clue involves 6 suspects, 6 weapons, and 9 rooms. one of each is randomly chosen and the object of the game is to gu
mina [271]
Part A:

Given that t<span>he game of clue involves 6 suspects, 6 weapons, and 9 rooms.

The number of ways that one of each is randomly chosen is given by:

^6C_1\times{ ^6C_1}\times{ ^9C_1}=6\times6\times9=324

Therefore, the number of solutions possible is 324.



Part B:

Given that a </span>players is randomly given three of the remaining cards, <span>let s, w, and r be, respectively, the numbers of suspects, weapons, and rooms in the set of three cards given to a specified player.

The number of suspects, weapons, and rooms remaining respectively after the player observes his or her three cards are: 6 - s, 6 - w, and 9 - r.

Let x denote the number of solutions that are possible after that player observes his or her three cards, then:

x={ ^{6-s}C_1}\times{ ^{6-w}C_1}\times{ ^{9-r}C_1}=(6-s)(6-w)(9-r)

Therefore, x in terms of s, w, and r is given by x = (6 - s)(6 - w)(9 - r).



Part C:

The expected value E(x) of a data set x_i with probabilities p(x_i) is given by E(x)=\Sigma xp(x)

There are </span>^{3+3-1}C_{3-1}={ ^5C_2}=10 possible combinations s, w and r. They are (3, 0, 0), (0, 3, 0), (0, 0, 3), (2, 1, 0), (0, 2, 1), (1, 0, 2), (2, 0, 1), (1, 2, 0), (0, 1, 2), (1, 1, 1)

Thus the expected value is given by

E(x)=3\cdot6\cdot9p(3, 0, 0)+6\cdot3\cdot9p(0, 3, 0)+6\cdot6\cdot6p(0, 0, 3) \\ 4\cdot5\cdot9p(2, 1, 0)+6\cdot4\cdot8p(0, 2, 1)+5\cdot6\cdot7p(1, 0, 2)+4\cdot6\cdot8p(2, 0, 1) \\ +5\cdot4\cdot9p(1, 2, 0)+6\cdot5\cdot7p(0, 1, 2)+5\cdot5\cdot8(1, 1, 1) \\  \\ = \frac{1}{ ^{21}C_3} (162\cdot{ ^6C_3}\cdot{ ^6C_0}\cdot{ ^9C_0}+162\cdot{ ^6C_0}\cdot{ ^6C_3}\cdot{ ^9C_0}+216\cdot{ ^6C_0}\cdot{ ^6C_0}\cdot{ ^9C_3} \\ \\ +180\cdot{ ^6C_2}\cdot{ ^6C_1}\cdot{ ^9C_0}+192\cdot{ ^6C_0}\cdot{ ^6C_2}\cdot{ ^9C_1}

+210\cdot{ ^6C_1}\cdot{ ^6C_0}\cdot{ ^9C_2}+192\cdot{ ^6C_2}\cdot{ ^6C_0}\cdot{ ^9C_1}+180\cdot{ ^6C_1}\cdot{ ^6C_2}\cdot{ ^9C_0} \\  \\ +210\cdot{ ^6C_0}\cdot{ ^6C_1}\cdot{ ^9C_2}+200\cdot{ ^6C_1}\cdot{ ^6C_1}\cdot{ ^9C_1} \\  \\ =\frac{1}{1,330}(324\cdot20+216\cdot84+360\cdot90+384\cdot135+420\cdot216+200\cdot324) \\  \\ =\frac{1}{1,330}(6,480+18,144+32,400+51,840+90,720+64,800) \\  \\ =\frac{1}{1,330}(264,384) \\  \\ =\bold{198.78}
6 0
3 years ago
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