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3 years ago

5

HURRY PLEASEEEEE I RLLY NEED THISSS

2 answers:

lilavasa [31]3 years ago

8 0

Answer:

Option 2

Step-by-step explanation:

Given function:

x=8 and y=6
x=5 and y=20

<em><u>Option 1: ×</u></em>

Table one: y=8-6

if y is 6 then 8-6 can’t be 6 it is 2.

<u><em>Option 2: √</em></u>

Table one:

y=8-2

y would be 6 then this would be correct..

Table two:

y=4x

if y=20 then x would be 5 and if y is 16 then x=4.

<u><em>Option 3:×</em></u>

y=4x

this is wrong since table 2 is y=4x..

<u><em>Option 4:×</em></u>

Table one

y=x-4

if y is 6 and x is 8 then this is wrong..

Therefore, option 2 is correct..

NemiM [27]3 years ago

3 0

The answer is option 2

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Please help me I need all this work done

svetoff [14.1K]

Answer:

31°

Step-by-step explanation:

Transversal BD crosses parallel lines AB and CD, creating alternate interior angles ∠2 and ∠5. As you know, alternate interior angles are congruent, so have the same measure.

m∠5 = m∠2 = 31°

8 0

3 years ago

Kendra owns a restaurant. She charges $3.00 for two eggs and one piece of toast and $1.80 for one egg and one piece of toast. Ho

Shkiper50 [21]

Lets t = # pieces of toast
e = # of eggs

2e + t = 3
e + t = 1.8
----------------subtract
e = 1.2
t = 1.8 - e
t = 1.8 - 1.2
t = 0.6

answer
<span>Kendra charges $1.2 per egg and 60 cents per toast</span>

5 0

3 years ago

Read 2 more answers

Simplify (5^3)^6 leaving your answer in index form.

Ket [755]

Answer:

5^18.

Step-by-step explanation:

By the law of indices:

(a^b)^c = a^(bc)

So (5^3)^6

= 5^(3*6)

= 5^18.

4 0

3 years ago

Give the place value of the 5 in the given number. 63,475 a. ones c. hundreds b. tens d. thousands

ivolga24 [154]

Ones because it is the last place value

5 0

3 years ago

Consider the following sets of sample data: A: $30,500, $27,500, $31,200, $24,000, $27,100, $28,600, $39,100, $36,900, $35,000,

Alecsey [184]

Answer:

$CV=0.2$ ---- dataset 1

$CV = 7.2$ --- dataset 2

Step-by-step explanation:

Given

$A: 30500, 27500, 31200, 24000, 27100,28600, 39100, 36900, 35000, 21400, 37900, 27900, 18700,$ $33100$

$B: 4.29, 4.88, 4.34, 4.17, 4.52, 4.80, 3.28, 3.79, 4.84, 4.77, 3.11$

Required

The coefficient of variation of each

<u>Dataset A</u>

Calculate the mean

$\mu = \frac{\sum x}{n}$

$\mu = \frac{30500+ 27500+31200+24000+ 27100+28600+ 39100+ 36900+ 35000+ 21400+ 37900+ 27900+ 18700+33100}{14}$ $\mu = \frac{418900}{14}$

$\mu = 29921.43$

Next, calculate the standard deviation using:

$\sigma = \sqrt{\frac{\sum(x - \mu)^2}{n}}$

So, we have:

$\sigma= \sqrt{\frac{(30500 - 29921.43)^2 +.................+ (18700- 29921.43)^2 + (33100- 29921.43)^2}{13}}$

$\sigma= \sqrt{\frac{487723571.42857}{14}}$

$\sigma= \sqrt{34837397.959184}$

$\sigma= 5902.32$

So, the coefficient of variation is:

$CV=\frac{\sigma}{\mu}$

$CV=\frac{5902.32}{29921.43}$

$CV=0.2$ --- approximated

<u>Dataset B</u>

Calculate the mean

$\mu = \frac{\sum x}{n}$

$\mu = \frac{4.29+ 4.88+ 4.34+ 4.17+ 4.52+ 4.80+ 3.28+ 3.79+ 4.84+ 4.77+ 3.11}{11}$

$\mu = \frac{46.79}{11}$

$\mu = 4.25$

Next, calculate the standard deviation using:

$\sigma = \sqrt{\frac{\sum(x - \mu)^2}{n}}$

$\sigma = \sqrt{\frac{(4.29 - 4.25)^2 + (4.88- 4.25)^2 +.........+ (3.11- 4.25)^2}{11}}$

$\sigma = \sqrt{\frac{3.859}{11}}$

$\sigma = \sqrt{0.35081818181}$

$\sigma = 0.593$

So, the coefficient of variation is:

$CV=\frac{\sigma}{\mu}$

$CV = \frac{4.25}{0.5903}$

$CV = 7.2$ -- approximated

3 0

3 years ago