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erik [133]
2 years ago
5

Write a fraction that is equivalent to 3/4 with a denominator of 20

Mathematics
2 answers:
saw5 [17]2 years ago
6 0

Answer:

3 / 4 =  15 / 20

Step-by-step explanation:

I think thats right

Nat2105 [25]2 years ago
4 0

Answer:

15/20

Step-by-step explanation:

1. Take the denominator of 3/4 and multiply it by 5 because that is what it takes to get 20 from 4.

4 x 5 = 20.

2. Multiply the numerator by 5 as well.

15/20

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In which direction must the graph of Rx) = 7% be shifted to produce the graph of g(x) = 7% + 7?
joja [24]

Answer:

B. Up

Step-by-step explanation:

If you alter a function by adding or subtracting a constant to the end of the expression, then the graph will slide up (down if subtracting) If you alter the x value by altering the expression in close to the x with addition or subtraction the graph will slide left or right.

Vertical translations (sliding up or down) go up when adding and down when subtracting as you would expect it to.

Horizontal translations are the oppoof what you might expect. A (x-h) will shift the graph right, while a (x+k) will shift the graph left.

The answer to your question is UP.

5 0
2 years ago
What equation is graphed in this figure?
Ksivusya [100]

to get the equation of any straight line, we simply need two points off of it, let's use those two points in the picture below.

(\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{5}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{5}-\stackrel{y1}{2}}}{\underset{run} {\underset{x_2}{1}-\underset{x_1}{0}}}\implies \cfrac{3}{1}\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_2=m(x-x_2) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_2}{5}=\stackrel{m}{3}(x-\stackrel{x_2}{1})

keeping in mind that for the point-slope form, either point will do, in this case we used the second one, but the first one would have worked just the same.

7 0
1 year ago
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slava [35]

Answer:

the answer is 2119

Step-by-step explanation:

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3 0
3 years ago
The chart below lists the original and sale prices of items at a clothing store.
Tom [10]

Answer: C) For every original price, there is exactly one sale price.

For any function, we always have any input go to exactly one output. The original price is the input while the output is the sale price. If we had an original price of say $100, and two sale prices of $90 and $80, then the question would be "which is the true sale price?" and it would be ambiguous. This is one example of how useful it is to have one output for any input. The input in question must be in the domain.

As the table shows, we do not have any repeated original prices leading to different sale prices.

5 0
3 years ago
Read 2 more answers
Pleaseeee helpppp ):
tigry1 [53]

Answer:

4

_

3.14159265358979323846264338327952884197169393751

3 0
2 years ago
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