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bulgar [2K]
3 years ago
14

Tom went on a bike to the store 3 miles away. If it took Tom 1/2 of an hour to get there and 2/3 of an hour to get back , what w

as his average rate of speed for the entire trip
Mathematics
1 answer:
anastassius [24]3 years ago
8 0

Answer:

5.14 mi/h

Step-by-step explanation:

To find the average speed, we simply find the total distance traveled by Tom and divide that by the total time the entire journey took him.

Average speed = (total distance traveled) / (total time taken)

TOTAL DISTANCE TRAVELED

He traveled 3 miles to and 3 miles fro. Hence:

3 + 3 = 6 miles

TOTAL TIME TAKEN

He spent ½ hr to go and ⅔ hr to return back. Hence:

½ + ⅔ = 7/6 hr

Therefore, the average speed is:

v = 6 / (7/6)

v = 36 / 7 = 5.14 mi/h

Tom's average speed was 5.14 mi/h.

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Solve Q=3a+5ac for a
lilavasa [31]
Here is how you solve... 

Q= 3a+5ac 

take out the common variable.
Q= a(3+5c)

get A by its self so divide each side by (3+5c).
Q/a(3+5c)= a(3+5c)/(3+5c)

Q/a(3+5c)=A

So your answer is A= Q/a(3+5c)

hope that helped.
8 0
3 years ago
What is the total paid back on a loan of $1,500 with an interest rate of 3.74% for 2 years?
zheka24 [161]

Answer:

1612.2

Step-by-step explanation:

3.74% × 2 = 7.48%

1500 + 7.48% = 1612.2

5 0
2 years ago
Read 2 more answers
The base of a solid crate has an area of 6 square meters.The height of the crate is 4 meters. What is the volume of the crate?
professor190 [17]

Given is the base area of a solid crate, B = 6 square meters.

Given is the height of the solid crate, H = 4 meters.

We know the formula for volume of any solid is given as follows :-

(Volume of the solid) = (Base area of the solid) x (Height of the solid).

Volume = B x H.

Volume = (6 square meters) x (4 meters).

Volume = 24 cubic meters.

Hence, the volume of the solid crate would be 24 cubic meters.

6 0
3 years ago
Read 2 more answers
A ball is dropped from a height of 10 feet and returns to a height that is one-half of the height from which it fell. The ball c
ANTONII [103]
1st drop- 10ft comes back up 5ft
2nd drop-5ft comes back up 2.5ft
3rd drop-2.5ft comes back up 1.25 ft
4th drop-1.25ft comes back up .625ft

(10+5) + (5+2.5) + (2.5+1.25) + (1.25) = 27.5ft
7 0
3 years ago
At one point the average price of regular unleaded gasoline was ​$3.41 per gallon. Assume that the standard deviation price per
Aleonysh [2.5K]

Answer:

a)  1-\frac{1}{k^2} =1- \frac{1}{2^2}= 1-0.25 = 0.75

So we expected about 75% within two deviations from the mean

b) 1-\frac{1}{k^2} =1- \frac{1}{1.5^2}= 1-0.4444 = 0.556

So we expected about 55.6% within 1.5 deviations from the mean

And the limits are:

Lower = 3.41 -1.5*0.09 = 3.275

Upper = 3.41 +1.5*0.09 = 3.545

c) We can calculate how many deviations we are within the mean with the limits with this formula:

z =\frac{x-\mu}{\sigma}

And using the lower limit we got:

z = \frac{3.05-3.41}{0.09}=-4

And with the upper limit we got:

z = \frac{3.77-3.41}{0.09}=4

So then the value of k =4 and the percentage is given by:

1-\frac{1}{k^2} =1- \frac{1}{4^2}= 1-0.0625 = 0.9375

Step-by-step explanation:

Previous concepts and Data given  

\mu =3.41 reprsent the population mean

\sigma=0.09 represent the population standard deviation

The Chebyshev's Theorem states that for any dataset

• We have at least 75% of all the data within two deviations from the mean.

• We have at least 88.9% of all the data within three deviations from the mean.

• We have at least 93.8% of all the data within four deviations from the mean.

Or in general words "For any set of data (either population or sample) and for any constant k greater than 1, the proportion of the data that must lie within k standard deviations on either side of the mean is at least: 1-\frac{1}{k^2}

Part a

For this case we can find the percentage required replaincg k =2 and we got:

1-\frac{1}{k^2} =1- \frac{1}{2^2}= 1-0.25 = 0.75

So we expected about 75% within two deviations from the mean

Part b

For this case we can find the percentage required replaincg k =2 and we got:

1-\frac{1}{k^2} =1- \frac{1}{1.5^2}= 1-0.4444 = 0.556

So we expected about 55.6% within 1.5 deviations from the mean

And the limits are:

Lower = 3.41 -1.5*0.09 = 3.275

Upper = 3.41 +1.5*0.09 = 3.545

Part c

We can calculate how many deviations we are within the mean with the limits with this formula:

z =\frac{x-\mu}{\sigma}

And using the lower limit we got:

z = \frac{3.05-3.41}{0.09}=-4

And with the upper limit we got:

z = \frac{3.77-3.41}{0.09}=4

So then the value of k =4 and the percentage is given by:

1-\frac{1}{k^2} =1- \frac{1}{4^2}= 1-0.0625 = 0.9375

3 0
3 years ago
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