Answer:
the firsts third and last one
Step-by-step explanation:
hope this helped
Answer:
-13
Step-by-step explanation:
-5-8= -13
If each linear dimension is scaled by a factor of 10, then the area is scaled by a factor of 100. This is because 10^2 = 10*10 = 100. Consider a 3x3 square with area of 9. If we scaled the square by a linear factor of 10 then it's now a 30x30 square with area 900. The ratio of those two areas is 900/9 = 100. This example shows how the area is 100 times larger.
Going back to the problem at hand, we have the initial surface area of 16 square inches. The box is scaled up so that each dimension is 10 times larger, so the new surface area is 100 times what it used to be
New surface area = 100*(old surface area)
new surface area = 100*16
new surface area = 1600
Final Answer: 1600 square inches
Okay, so here, we know that -10 is the slope, therefore, it is also the constant of proportionality.
'x' is the unknown value, that tells us to multiply by -10.
So, on a graph, we would consider that per unit, it would decrease by -10, since its a negative slope.
Hope I helped, if you have further questions or concerns, feel free to PM me. Thanks! :D
<h3>
Answer: -i</h3>
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Explanation:
i = sqrt(-1)
Lets list out the first few powers of i
- i^0 = 1
- i^1 = i
- i^2 = -1
- i^3 = i*i^2 = i*(-1) = -i
- i^4 = (i^2)^2 = (-1)^2 = 1
By the time we reach the fourth power, we repeat the cycle over again (since i^0 is also equal to 1). The cycle is of length 4, which means we'll divide the exponent over 4 to find the remainder. Ignore the quotient. That remainder will determine if we go for i^0, i^1, i^2 or i^3.
For example, i^5 = i^1 because 5/4 leads to a remainder 1.
Another example: i^6 = i^2 since 6/4 = 1 remainder 2
Again, we only care about the remainder to find out which bin we land on.
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Turning to the question your teacher gave you, we have,
739/4 = 184 remainder 3
So i^739 = i^3 = -i
<h3>
-i is the final answer</h3>
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Side notes:
- if i^a = i^b, then a-b is a multiple of 4
- Recall that the divisibility by 4 trick involves looking at the last two digits of the number. So i^739 is identical to i^39.
