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Korvikt [17]
2 years ago
12

Need help ASAP please!!!!

Mathematics
1 answer:
kenny6666 [7]2 years ago
4 0

Answer:

72 divided by 8 = t

Step-by-step explanation:

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The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l
sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

A=\frac{\sqrt{3} }{4} x^2

(c)

A=\frac{3\sqrt{3} }{2} x^2

(d)

V=\frac{3\sqrt{3} }{2} x^3 units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

=\frac{\sqrt{3} }{4} b^2

h=3x

b=x

now, we can plug values

A=\frac{\sqrt{3} }{4} x^2

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

=6\times \frac{\sqrt{3} }{4} x^2

=\frac{3\sqrt{3} }{2} x^2

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)

V=\frac{3\sqrt{3} }{2} x^3 units^3


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3 years ago
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So first, this is point slope form. The first step is to distribute.)
y-4=-2x-6
Then add 4 to both sides.
y=-2x-2
Then add 2x and it becomes
2x+y=-2
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3 years ago
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What is 5 tenth of 2 tenth
Fudgin [204]
5/10 and 2/10 beacuse tenth is the bottom number
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Tpy6a [65]
The six trigonometric functions are sine, cosine, tangent, cotangent, secant and cosecant. This is a first quadrant angle. sine of -17 pi over 3 is equal to square root of 3 over 2, cosine of -17 pi over 3 is equal to 1/2. tan -17 pi over 3  is equal to square root of 3. cosecant-17 pi over 3  is equal to 2/sqrt3, secant  of -17 pi over 3 is 2 while cotangent -17 pi over 3  is equal to 1/sqrt 3
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For t=2 , 14t−3t is equal to ____? and 3t−14t is equal to ____?
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Answer:

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  1. 3t-14t= -22
  2. where there is t multiply by 2
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