Answer:
The lengths of sides of squares are 5 cm and 9 cm.
Step-by-step explanation:
Let the sides of rectangle be x and y .
Area of rectangle = Length × Breadth
Given : Area of rectangle = 45 cm².
⇒ x × y = 45
⇒
........(1)
Two squares are constructed such that two adjacent sides of the rectangle
so squares have side x and y .
Area of square = side × side
Area of square with side x = x²
Area of square with side y = y²
Also, The combined area of the two squares is 106 cm².
⇒ x² + y² = 106
From (1) put value of x , we get,
![(\frac{45}{y})^2+y^2=106](https://tex.z-dn.net/?f=%28%5Cfrac%7B45%7D%7By%7D%29%5E2%2By%5E2%3D106)
Solving for y ,
![(y^2-25)(y^2-81)=0](https://tex.z-dn.net/?f=%28y%5E2-25%29%28y%5E2-81%29%3D0)
or
on solving we get y = 5 and y = 9
Also, x can be find by putting in (1),
⇒
and ⇒
⇒ x = 9 and x = 5
Thus, lengths of sides of squares are 5 cm and 9 cm.