Let x be total hours of battery life. We have been given that battery life of Vera's phone is down to 2/5. So remaining battery life,
We have been also given that it drains another 1/9 every other hour. Now let us substitute our given information into an equation.
Now we will solve for x.
Let us convert 2/5 into minutes. We know 1 hour has 60 minutes.
Therefore, remaining battery life will be 5 hours and 24 minutes.
Factor out 12x^3y^2
12x^3y^2(3y^2+5x^ 2 y z^2 -1)
Simplify <span>22\times 2<span>22×2</span></span> to <span>44<span>44</span></span>
<span><span>{x}^{4}+44-16x-12<span><span>x<span><span>4</span><span></span></span></span>+44−16x−12</span></span>Collect like terms
<span><span>{x}^{4}+(44-12)-16x<span><span>x<span><span>4</span><span></span></span></span>+(44−12)−16x</span></span> Simplify</span><span><span>{x}^{4}+32-16x<span><span>x<span><span>4</span><span></span></span></span>+32−16x</span></span><span>
</span></span></span>
SLope = (2 + 2)/(2 + 2) = 4/4 = 1
Answer
1
