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malfutka [58]
2 years ago
15

Give another name for RS.

Mathematics
2 answers:
Zigmanuir [339]2 years ago
7 0

Answer:

Step-by-step explanation:

Arte-miy333 [17]2 years ago
7 0
Answer: SR because it is still meaning the same segment just a different way of naming it
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A software company is releasing one of their products on a CD. The manufacturer charges a $9700 setup fee and $1.25 per CD. Appr
Gre4nikov [31]

Answer:

  about 4312

Step-by-step explanation:

You want the total cost for n CDs to be 3.50n.

The manufacturer will charge you 9700+1.25n, so you want these to be equal:

  3.50n = 9700 +1.25n

  2.25n = 9700 . . . . . . . . subtract 1.25n

  n = 9700/2.25 ≈ 4311.111...

Producing 4312 CDs will make the cost per CD slightly less than $3.50.

____

Producing 4311 CDs will make the cost per CD be about $3.500058. Producing 4312 CDs will bring it down to $3.499536.

3 0
2 years ago
Create a set of coordinates to model a relation that is a linear function.
STALIN [3.7K]
I will create a set of arbitrary constants (x1,y1) (x2,y2)

slope = y2-y1/x2-x1

y = (y2-y1/x2-x1)x + b

y2 = (y2-y1/x2-x1)x2 + b

b = y2 - (y2-y1/x2-x1)x2

y = (y2-y1/x2-x1)x + [y2 - (y2-y1/x2-x1)]

Choose any points and just 
Plug the values and you have a linear function.

NOT SURE IF THAT'S WHAT THE QUESTION WANTS.





3 0
3 years ago
1 point
arsen [322]

Answer:

the answer is 32 :)

hope this helps

8 0
3 years ago
Read 2 more answers
Express the terms of the following geometric sequence recursively.
BabaBlast [244]

Answer:

The most correct option for the recursive expression of the geometric sequence is;

4. t₁ = 7 and tₙ = 2·tₙ₋₁, for n > 2

Step-by-step explanation:

The general form for the nth term of a geometric sequence, aₙ is given as follows;

aₙ = a₁·r⁽ⁿ⁻¹⁾

Where;

a₁ = The first term

r = The common ratio

n = The number of terms

The given geometric sequence is 7, 14, 28, 56, 112

The common ratio, r = 14/7 = 25/14 = 56/58 = 112/56 = 2

r = 2

Let, 't₁', represent the first term of the geometric sequence

Therefore, the nth term of the geometric sequence is presented as follows;

tₙ = t₁·r⁽ⁿ⁻¹⁾ = t₁·2⁽ⁿ⁻¹⁾

tₙ =  t₁·2⁽ⁿ⁻¹⁾ = 2·t₁2⁽ⁿ⁻²⁾ = 2·tₙ₋₁

∴ tₙ = 2·tₙ₋₁, for n ≥ 2

Therefore, we have;

t₁ = 7 and tₙ = 2·tₙ₋₁, for n ≥ 2.

4 0
3 years ago
WILL MARK CORRECT ANSWERS BRAINLIEST! MATH PLEASE HELP DUE TODAY ASAP!!!
pentagon [3]

Answer:

Image #1:      A. 0

Image #2:    D. y = -(<em>z</em> - 5)² + 3

Image #3:      ( -0.333, 0.111 )

Image #4:     B. -4 and 2

Image #5:     y = -x²

~Hope this helps!~

7 0
3 years ago
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