It would be 10x5 + 3x8= 74
Answer:
one hundred and ninety two point zero seven
Step-by-step explanation:
idk guess
The value of x in the secants intersection is 1 units
The value of NM in the tangent and secant intersection is 51 units
<h3>How to find length when secant and tangent intersect?</h3>
The first question, two secant intersect outside the circle.
Therefore,
(6x + 8x)8x = (9 + 7)7
14x(8x) = 16(7)
112x² = 112
x² = 112 / 112
x = √1
x = 1
The second question, tangent and secant intersect,
Therefore,
(x + 3)² = (x - 3)(16 + x - 3)
(x + 3)² = (x - 3)(x + 13)
(x + 3)(x + 3) = (x - 3)(x + 13)
x² + 3x + 3x + 9 = x² + 13x - 3x - 39
x² + 9x + 9 = x² + 10x - 39
x² - x² + 9x - 10x = -39 - 9
-x = - 48
x = 48
NM = 48 + 3 = 51 units
learn more on secant and tangent here: brainly.com/question/12477905
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Hi there!
Use the Pythagorean theorem to find the length of the line.
If we draw an imaginary right triangle using the given line as the hypotenuse, we can derive a height of 6 units and a length of 10 units.
Use the Pythagorean theorem equation:
c² = a² + b²
Plug in the height and length:
c² = 6² + 10²
Simplify:
c² = 36 + 100
c² = 136
Take the square root of both sides:
c = √136. The correct answer is D.
Answer:
I think its 256
Step-by-step explanation:
The LCM of 128 and 256 is 256. Steps to find LCM. Find the prime factorization of 128 128 = 2 × 2 × 2 × 2 × 2 × 2 × 2; Find the prime factorization of 256.
