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zlopas [31]
3 years ago
14

Find the 7th term for the sequence with the given formula.

Mathematics
2 answers:
Step2247 [10]3 years ago
7 0

Answer:

11

Step-by-step explanation:

AveGali [126]3 years ago
3 0

Answer:

46.

Step-by-step explanation:

tn = n^2 - 3

7th term = t7

= 7^2 - 3

= 49 - 3

= 46.

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Please help me!!!! precalc question
dangina [55]

Step-by-step explanation:

1. Ampltiude is 1

The period is

\frac{2\pi}{3}

is the period

The phase shift is 0

2. The Ampltiude is 2

The period is 2 pi

The phase shift is 1

3. The amplitude is 3

The period is 2 pi/3

The phase shift is -2

4.The amplitude is 2/3

The period is -10pi

The phase shift is 0

5. The Ampltiude is 1

The period is -2 pi

The phase shift is pi

6. The amplitude is 1/4

The period is -4pi

The phase shift is negative 2pi/3

7. The Ampltiude is 3

The period is 4

The phase shift is 8

7 0
3 years ago
The graph of a linear equation has a slope of -2 and passes through point (-4, 3 ) what is the equation of the line
Irina-Kira [14]

Answer:

(-4,3)=x1,y1

m=-2

we have

y-y1=m(x-x1)

y-3=-2(x+4)

y-3=2x+8

2x-y+11=0 is the eqn

4 0
3 years ago
You are buying a new internet service. The service costs \$75$75 per month. In the equation below, dd is the total number of dol
Masja [62]

the months are independent

as well as the $75

the answer is dependent

3 0
3 years ago
Read 2 more answers
Is Event B dependent or independent of Event A? A: A green ball is drawn from a box with five balls and placed next to the box.
Zarrin [17]

Answer:

Step-by-step explanation:

Given that events are as follows:

A: A green ball is drawn from a box with five balls and placed next to the box. B: A red ball is drawn next and placed next to the green one

i.e. drawings of balls are made without replacement

Suppose there are m green balls and n red balls, where m+n =5

Prob of drawing green ball =m/5

After I draw made remaining are n red balls and m-1 green balls

Prob of drawing red ball now =n/4

Prob for drawing one green and one red simultaneously = \frac{mC1*nC1}{5C2} \\= \frac{mn}{10}

Product of the two probabilities = \frac{m}{5} *\frac{n}{4} \\=\frac{mn}{20}

6 0
4 years ago
Can someone please help me on this
PtichkaEL [24]

Well we know that all the sides are congruent so you can use SSS

There are two sides and one angle that is congruent therefore SAS

You have pairs of legs that are congruent so  LL

Lastly we know that JK and QR are congruent so you get HA

Hope this helps :)

6 0
4 years ago
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