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kramer
3 years ago
14

Explain why (1/2) sqaured 4 = 1/16

Mathematics
2 answers:
natka813 [3]3 years ago
7 0

Step-by-step explanation:

(\frac{1}{2})^4 = (\frac{ 1^4 }{2^4}) = (\frac{1}{16})

HOPE THIS HELPS

Sedaia [141]3 years ago
5 0

Answer:

1. 1/2 is multiplied to itself 2 times

1/2 x 1/2= 1/4

2. 1/4 is multiplied times 4

1/4 x 4=1/16

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Given the information below, write the equation in Standard Form.
Sergio [31]

Answer:

The standard form of the equation of the parabola is (y + 2)² = 8 (x - 3)

Step-by-step explanation:

The standard form of the equation of a parabola is (y - k)² = 4p (x - h), where

  • The vertex of the parabola is (h , k)
  • The focus is (h + p, k)

∵ The vertex of the parabola is (3 , -2)

∴ h = 3 and k = -2

∵ The focus is (5 , -2)

∴ h + p = 5

- Substitute h by 3 to find p

∵ 3 + p = 5

- Subtract 3 from both sides

∴ p = 2

∵ The standard form of the equation of the parabola is (y - k)² = 4p (x - h)

- Substitute the values of h , k , and p in the equation

∴ (y - -2)² = 4(2) (x - 3)

∴ (y + 2)² = 8 (x - 3)

The standard form of the equation of the parabola is (y + 2)² = 8 (x - 3)

3 0
3 years ago
Please help ASAP !!!!!!!!!!!! 20 Points!!!! The table shows the ratio of cheddar corn to hot pepper corn in a bag. What is the c
Murljashka [212]

Divide the amount of cheddar by the amount of hot pepper:

10 / 4 = 2.5

20 / 8 = 2.5

30 / 12 = 2.5


The constant is C.2.5

3 0
3 years ago
Read 2 more answers
What is the distance between the points ( 19, 4) and (11, 12)?
Olenka [21]
D = \sqrt{(x_{2}- x_{1})^{2}+ (y_{2} -y_{1})^{2}}
D = √(11-19)²+(12-4)²
D = √(-8)²+(8)²
D = √64+64
D = √128
D ≈ 11.3137 
8 0
2 years ago
If a can of paint covers 300 sq. feet, how many cans must be purchased to paint a wall 20 feet by 50 feet?
Serhud [2]
You need 4 Or exactly 3 and 1/3 paint cans because the area would be 1000 feet
5 0
3 years ago
A trapezoidal prism undergoes a dilation. The surface area of the pre-image is 35 m². The surface area of the image is 315 m². T
Westkost [7]

The original object is called pre-image, and its dilated version is called image. The height of the image for the considered case is 17.4 m

<h3>How does dilation affect length, area, and volume of an object?</h3>

Suppose a figure (pre image) is dilated (dilated image) by scale factor of k.

So, if a side of the figure is of length L units, and that of its similar figure is of M units, then:

<u><em>L = k × M</em></u>

where 'k' will be called as scale factor.

The linear things grow linearly like length, height etc.

The quantities which are squares or multiple of linear things twice grow by square of scale factor. Thus, we need to multiply or divide by <u><em>k²</em></u><em> </em>to get each other corresponding quantity from their similar figures' quantities.

<u><em>So </em></u><u><em>area </em></u><u><em>of </em></u><u><em>first figure </em></u><u><em>= k² × area of second figure</em></u>

Similarly,

<u><em>Volume </em></u><u><em>of first figure = k³ × volume of second figure.</em></u>

It is because we will need to multiply 3 linear quantities to get volume, which results in k getting multiplied 3 times, thus, cubed.

For this case, we're given that;

  • Surface area of pre-image = 35 m²
  • Surface area of dilated image = 315 m²
  • Height of pre-image = 5.8 m
  • Height of dilated image.

Let the scale fator of dilation be k.

Then:

<u><em>So area of pre-image = k² × area of dilated image</em></u>

Thus, we get:

35 = k^2 \times 315\\\\k = \sqrt{\dfrac{35}{315}} = 1/3

(took positive root as scaling is done by non-negative factors as only magnitude matters mostly)

Thus, we get:

Height of pre-image = (1/3) × Height of dilated image (say h)

5.8 = (1/3) \times h\\h = 3 \times 5.8 = 17.4 \rm \: m

Thus, the original object is called pre-image, and its dilated version is called image. The height of the image for the considered case is 17.4 m

Learn more about dilation here:

brainly.com/question/3266920

4 0
2 years ago
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