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Sholpan [36]
4 years ago
8

a postage stamp 25 millimeters wide and 40 millimeters tall is enlarged to make a poster. the poster is 4 feet wide. find the he

ight of the poster.
Mathematics
1 answer:
slava [35]4 years ago
3 0
I come from a place that does not use feet as a measurement metric, so I googled the conversion metrics (correct me if I am wrong)
 
\boxed {1 foot = 304.8 \ millimeters}

----------------------------------------------------------------------------------------------
Find the scale factor between the stamp and the poster
----------------------------------------------------------------------------------------------
Stamp : Poster
25mm : 4 feet
25mm : 4 x 304.8
25mm : 1219.2mm
1mm : 48.768mm

\boxed {1 : 48.768}

----------------------------------------------------------------------------------------------
Find the missing height
----------------------------------------------------------------------------------------------
Stamp : Poster
40mm : 40 x 48.768mm
40mm : 1950.72mm

\boxed {1950.72mm}

----------------------------------------------------------------------------------------------
Convert back to feet
----------------------------------------------------------------------------------------------
40mm : 1950.72 ÷ 304.8 ft
40mm : 6.4 ft

\boxed {6.4 ft}
----------------------------------------------------------------------------------------------
Answer
----------------------------------------------------------------------------------------------
Height of the poster is 6.4ft

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Answer:

(assuming all members of the gang get equal percentages)

For a gang of 8: 12.5% (100/8)

If 2 are killed: 16.67% (100/6), so percentage increases by roughly 4.2% (16.67-12.5)

Percent that belongs to 3: 12.5%*3=37.5%

Percent that belongs to 3 if 2 are killed: 16.67%*3=50.0%

Each robber's share still increases by 4.2% (50%-37.5%=12.5%, 12.5%/3=4.2%)

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A solid wooden toy is in the form of a hemisphere surmounted by a cone of same radius. The radius of hemisphere is 3.5cm and the
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Answer:

Explanation below.

Step-by-step explanation:

Given: Radius of hemisphere = radius of cone = r = 3.5 cm

Volume of  total wood used in making a toy = 166 ⅚ = 1001/6 cm³

Let h be height of a cone.

Volume of  total wood used in making a toy = volume of hemisphere + volume of cone

(⅔) × πr³ + (⅓)π²h

= (⅓)πr²(2r + h)

1001/6 = (⅓) ×( 22/7) × (3.5)² × (h +2×3.5)

1001/6 = (⅓) ×( 22/7) × 3.5 ×3.5 ×( h+7)

1001/6 = (⅓) ×  22 × .5 ×3.5 × (h +7)

1001 × 3  = 6 × 22 × .5 ×3.5 × (h+7)

h +7  = 1001 × 3 / (6 ×  22 × .5 ×3.5)

h +7 = 1001 × 3 / 132 × 1.75

h +7 = 1001 × 3 × 100 / 132 × 175

h +7 = 91 × 3 × 4 / 12 × 7

h +7 = 91 × 12 / 12×7

h +7 = 13

h + 7 = 13 -7 = 6

Height of a cone(h) = 6

Height of the toy = Height of a cone + Height of a hemisphere

Height of the toy = 6 +3.5 = 9.5 cm

Curved surface area of hemisphere = 2πr²

CSA of hemisphere = 2 ×( 22/7) × 3.5 × 3.5

= 2 × 22 × .5 × 3.5 = 44 × 1.75 = 77 cm²

Rate of painting the hemispherical part of the toy = ₹ 10 per m².

Cost of painting the hemispherical part of the toy = 77 × 10 =  ₹ 770 .

Hence, the Height of the toy is 9.5 m & Cost of painting the hemispherical part of the toy is  ₹ 770.

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