4 cos² x - 3 = 0
4 cos² x = 3
cos² x = 3/4
cos x = ±(√3)/2
Fixing the squared cosine doesn't discriminate among quadrants. There's one in every quadrant
cos x = ± cos(π/6)
Let's do plus first. In general, cos x = cos a has solutions x = ±a + 2πk integer k
cos x = cos(π/6)
x = ±π/6 + 2πk
Minus next.
cos x = -cos(π/6)
cos x = cos(π - π/6)
cos x = cos(5π/6)
x = ±5π/6 + 2πk
We'll write all our solutions as
x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k
<span><span> t =(-12-√-21856)/-50=(6+2i√<span> 1366 </span>)/25= 0.2400-2.9568i</span><span> t =
(-12+√-21856)/-50=(6-2i√<span> 1366 </span>)/25= 0.2400+2.9568<span>i</span></span></span>
Answer:
This is the expression expanded
Step-by-step explanation:
35/18 or 1 17/18
Apply the fraction rule
5/6 * 7/3
Multiply
5*7/6*3
Answer
=35/18 or 1 17/18
U need the law of cosines and heron's formula
