Using the binomial distribution, it is found that there is a 0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.
For each die, there are only two possible outcomes, either a 3 or a 4 is rolled, or it is not. The result of a roll is independent of any other roll, hence, the <em>binomial distribution</em> is used to solve this question.
Binomial probability distribution
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- There are 9 rolls, hence
.
- Of the six sides, 2 are 3 or 4, hence

The desired probability is:

In which:

Then



Then:


0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.
For more on the binomial distribution, you can check brainly.com/question/24863377
Answer:
below
Step-by-step explanation:
76.98
56 is a decimal part of 70. 56 = 4/5 = .8
1,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000x3422222222222222222222224444444444444444444444443333333335
umka2103 [35]
Answer:100000000000000000000000000000 quint zillion
Step-by-step explanation:
Using the Punnette Square :
R r
<span>R RR Rr </span>
<span>r Rr rr
</span>Hence,
<span>By applying the rules of probability Rr x Rr, the probability of the offspring being homozygous recessive will be one fourth or a quarter.
SO the best is :
B. 1/4</span>