Solve for X. Y=2/3×-4
1 answer:
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Answer:0.246ft/s
Step-by-step explanation: when the the worker starts moving and stops 10 feets away from lateral rope connecting the load, it forms a right angle triangle as see in the pix.
V = s/t ... equ 1
S= distance traveled by worker while pulling the rope = 10 ft
V = velocity of worker = 2ft/s
T = time taken the worker to move 10 ft = time taken for the load to move up = 5seconds
Use Pythagoras theorem to determine distance from pulley to new position of worker
Square root of (40^2 + 10^2) = 41.23ft
Distance traveled by load = D = 41.23 - 40
=1.23ft
Speed of load = D/ t...equ2
Substituting D and the into equ2
S.l = speed of load = 1.23/5 =0.246ft/s
