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3 years ago

Answer help on this !

Mathematics

2 answers:

Arisa [49]3 years ago

8 0

If the triangles are similar, then the angles are all congruent.

Therefore, we can start by setting the two middle angles equal to each other.

4x + 7 = 5x - 10

7 = x - 10

x = 17

Middle angle = 75

Now that we know our x-value, we can simply plug in x for our other two expressions.

3 * 17 = 51

4(17) - 14 = 54

We can check to make sure that our angle measures are correct by adding them all up and making sure they equal 180.

54 + 51 + 75 = 180

180 = 180

Hope this helps!! :)

pentagon [3]3 years ago

5 0

Answer:

54, 51, 75

Step-by-step explanation:

4x+7=5x-10 because they are vertical angles and are therefore equal to eachother. x=17.

After plugging the 17 into the equations you get 4(17)+7=75. 3(17)=51. All angles in a triangle add up to 180. We already have 75 and 51 in the first triangle, to get the third length you need to subtract that from 180. 180-75+51=54.

The second triangle will give you the same lengths. 5x-10=75. 4(17)-14=54. Again, 180-75-54=51.

Your final lengths are 75,51,54.

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Liam Had 250. Then, he and his classmate buy present for their teacher, evenly splitting the P cost among the 24 of them. How mu

tamaranim1 [39]

If it was just the splitting It would be
Let L be the amount he has left
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8 0

4 years ago

Can I get some help

butalik [34]

4x + 2x -5(x - 3) = 18

4x + 2x - 5x - 15 = 18

4x + 2x - 5x = 18 + 15

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I'm not sure my answer is right or wrong

I hope it's helpful!!

8 0

3 years ago

Why are these triangles similar?

AveGali [126]

Answer:

I think they are similar by SAS.

Step-by-step explanation:

Both triangles may not be the same size, but they have similar sides and similar angles.

4 0

3 years ago

Find the seventh term of the

jekas [21]

Answer:

$T_7 = \frac{64}{729}$

Step-by-step explanation:

Given

$a =1$

$r = \frac{2}{3}$

Required

Determine the 7th term

The nth term of a gp is:

$T_n = a * r^{n-1$

So, we have:

$T_7 = 1 * \frac{2}{3}^{7-1$

$T_7 = 1 * \frac{2}{3}^{6$

$T_7 = 1 * \frac{2^6}{3^6}$

$T_7 = 1 * \frac{64}{729}$

$T_7 = \frac{64}{729}$

6 0

3 years ago

Consider the polynomials p(x) = 3x + 27x^2 and q(x)= 2 . Find the x -coordinate(s) of the point(s) of intersection of these two

Tom [10]

Answer:

The x -coordinate(s) of the point(s) of intersection of these two polynomials are $x=\frac{2}{9}\approx0.2222,\:x=-\frac{1}{3}\approx-0.3333$

The sum of these x -coordinates is $\frac{2}{9}+\left(-\frac{1}{3}\right)=-\frac{1}{9}$

Step-by-step explanation:

The intersections of the two polynomials, p(x) and q(x), are the roots of the equation p(x) = q(x).

Thus, $3x + 27x^2=2$ and we solve for x

$3x+27x^2-2=2-2\\27x^2+3x-2=0\\\left(27x^2-6x\right)+\left(9x-2\right)\\3x\left(9x-2\right)+\left(9x-2\right)\\\left(9x-2\right)\left(3x+1\right)=0$

Using Zero Factor Theorem: = 0 if and only if = 0 or = 0

$9x-2=0\\9x=2\\x=\frac{2}{9}$

$3x+1=0\\3x=-1\\x=-\frac{1}{3}$

The solutions are:

$x=\frac{2}{9}\approx0.2222,\:x=-\frac{1}{3}\approx-0.3333$

The sum of these x -coordinates is

$\frac{2}{9}+\left(-\frac{1}{3}\right)=-\frac{1}{9}$

We can check our work with the graph of the two polynomials.

4 0

4 years ago