Answer:
1. h
2. k
3. d
4. j
5. m
6. n
7. a
8. l
9. e
10. c
11. f
12. i
13. g
14. b
Step-by-step explanation:
1. a quotient of two quantities -> h. fraction
2. a quotient that involves variables -> k. algebraic fraction
3. numbers that would result in division by zero -> d. exclusions
4. multiply the numerators and multiply the denominators for a new fraction -> j. multiplication of fractions
5. multiply by the reciprocal of the divisor -> m. division of fractions
6. the denominators must be the same -> n. addition of fractions
7. contains a fraction in the numerator, denominator, or with the denominator -> a. complex fractions
8. a new fraction resulting from the interchanging of the numerator and denominator -> l. reciprocal
9. the dividend of a fraction -> e. numerator
10. the divisor in a fraction -> c. denominator
11. the lowest common multiple of denominators -> f. lowest common denominator
12. a combination of integral and fractional expressions -> i. mixed expression
13. an equation that contains fractions -> g. fractional equation
14. a statement that two fractions are equal -> b. proportion
Answer:
Step-by-step explanation:
use m a t h w a y
Answer:
Step-by-step explanation:
2 less then the product of 9 and a number is 4
" the product " is the result of multiplication
the product of 9 and a number...9x
2 less......-2
is 4...= 4
9x - 2 = 4 <===
Answer:
Below in bold.
Step-by-step explanation:
Area of a kite = 1/2 * D1 * D2 were D1 and D2 are the 2 diagonals
D1 = 5 + 2.5 = 7.5 and D2 = 2*44444.5 = 9
So area = 1/2 * 7.5 * 9
= 33.75.
The standard quantity of metal per ring is 0.57 kilograms.
Step-by-step explanation:
Each ring requires 0.52 kilograms of a special metal.
The allowance for waste is 0.03 kilograms per ring, while the allowance for rejects is 0.02 kilograms per ring.
So, the standard quantity of metal per ring = 0.52 kg of metal required + 0.03 kg of allowance for waste + 0.02 kg of allowance for rejects)
= 
kilograms.
Hence, the standard quantity of metal per ring is 0.57 kilograms.
