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3 years ago

3 + 2x - y = 0, -3 - 7y = 10x}

Mathematics

1 answer:

zvonat [6]3 years ago

3 0

Answer:

In point form:

( -1 , 1 )

In equation form:

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WILL GIVE BRAINLIEST!!!!!!!!!!

navik [9.2K]

Answer:

Here, Exterior angles are ∠1, ∠2, ∠7 and ∠8

Interior angles are ∠3, ∠4, ∠5 and ∠6

Corresponding angles are ∠

(i) ∠1 and ∠5

(ii) ∠2 and ∠6

(iii) ∠4 and ∠8

(iv) ∠3 and ∠7

Axiom 4 If a transversal intersects two lines such that a pair of corresponding angles is equal, then the two lines are parallel to each other.

Thus, (i) ∠1 = ∠5, (ii) ∠2 = ∠6, (iii) ∠4 = ∠8 and (iv) ∠3 = ∠7

Alternate Interior Angles: (i) ∠4 and ∠6 and (ii) ∠3 and ∠5

Alternate Exterior Angles: (i) ∠1 and ∠7 and (ii) ∠2 and ∠8

If a transversal intersects two parallel lines then each pair of alternate interior and exterior angles are equal.

Alternate Interior Angles: (i) ∠4 = ∠6 and (ii) ∠3 = ∠5

Alternate Exterior Angles: (i) ∠1 = ∠7 and (ii) ∠2 = ∠8

Interior angles on the same side of the transversal line are called the consecutive interior angles or allied angles or co-interior angles. They are as follows: (i) ∠4 and ∠5, and (ii) ∠3 and ∠6

5 0

3 years ago

Find the solution of the differential equation that satisfies the given initial condition. y' tan x = 3a + y, y(π/3) = 3a, 0 &lt

Paladinen [302]

Answer:

$y(x)=4a\sqrt{3}* sin(x)-3a$

Step-by-step explanation:

We have a separable equation, first let's rewrite the equation as:

$\frac{dy(x)}{dx} =\frac{3a+y}{tan(x)}$

But:

$\frac{1}{tan(x)} =cot(x)$

So:

$\frac{dy(x)}{dx} =cot(x)*(3a+y)$

Multiplying both sides by dx and dividing both sides by 3a+y:

$\frac{dy}{3a+y} =cot(x)dx$

Integrating both sides:

$\int\ \frac{dy}{3a+y} =\int\cot(x) \, dx$

Evaluating the integrals:

$log(3a+y)=log(sin(x))+C_1$

Where C1 is an arbitrary constant.

Solving for y:

$y(x)=-3a+e^{C_1} sin(x)$

$e^{C_1} =constant$

So:

$y(x)=C_1*sin(x)-3a$

Finally, let's evaluate the initial condition in order to find C1:

$y(\frac{\pi}{3} )=3a=C_1*sin(\frac{\pi}{3})-3a\\ 3a=C_1*\frac{\sqrt{3} }{2} -3a$

Solving for C1:

$C_1=4a\sqrt{3}$

Therefore:

$y(x)=4a\sqrt{3}* sin(x)-3a$

3 0

4 years ago

Use the polygon tool to graph the reflection of this rectangle across the x-axis.

iVinArrow [24]

Answer:

Step-by-step explanation:

From the figure attached,

Coordinates of the vertices of the given rectangle ABCD,

A(3, 6), B(12, 6), C(12, 1) and D(3, 1)

Rule for the reflection of a point across x-axis,

(x, y) → (x, -y)

After reflection of the given rectangle across x-axis image points will be,

A(3, 6) → A'(3, -6)

B(12, 6) → B'(12, -6)

C(12, 1) → C'(12, -1)

D(3, 1) → D'(3, -1)

Now we can plot these points on the graph to get the image of rectangle ABCD.

7 0

3 years ago

Read 2 more answers

Inequalities help please

Bingel [31]

The answer is B x is greater than -5 and less than 3

8 0

4 years ago

I need help with C, thank you.

guapka [62]

Simple....

$\frac{3}{4} x\ \textless \ \frac{9}{2}$

x<6

This means that on your graph at 6 it's a circle (not colored in) and it goes to the left indefinitely...

Thus, your answer.

6 0

3 years ago