In order to determine the results from a father who is homozygous recessive for the tongue rolling trait, T, and a mother who is heterozygous for the trait, a Punett square can be used to determine both the resulting genotype (allele combination) and phenotype (observable characteristics). The results are 50% Tt and 50% tt. Thus, the cross would result to 1:1 ratio of tongue rolling to non-tongue rolling offsprings.
Answer:
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The answer is c. Anaphase I separates homologous chromosomes and anaphase II separates sister chromatids into daughter cells.
Meiosis is a cell division which results in the reduction of chromosome number by half (from diploid to haploid) in daughter cells. It consists of meiosis I and meiosis II.
In anaphase I, the sister chromatids separate from each other to the opposite sides of the cells. In meiosis I there are 46 chromosomes in duplicates which are present as pairs of sister chromatids. When comes to separation, homologous chromosomes separates only, but not sister chromatids. Homologous chromosomes are present only in meiosis I.
In anaphase II, since the cell is haploid, there are 23 chromosomes in duplicates, which are present as sister chromatids. So, in this phase, sister chromatids are those who separates.
