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Readme [11.4K]
3 years ago
8

GEOMETRY. I need help Is this right or not?

Mathematics
1 answer:
meriva3 years ago
5 0

Answer:

Step-by-step explanation:

yea...................

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How many solutions does the equation |x+7|= -1 have?
KonstantinChe [14]

None.

The absolute value of something cannot be <em>negative</em>.

6 0
4 years ago
Find the inverse of h(x)
Brilliant_brown [7]

Answer:

f^{-1} (x) = \frac{x}{h}

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Select all input values for which g(x)=8
Naily [24]

Answer:

a. x = -4

c. x = 9

Step-by-step explanation:

Values of g(x), output values, are plotted on the y-axis, while the corresponding x values, input, of the function are plotted on the x-axis.

We are to determine all possible input values (x-values) that will give us an output value, g(x) = 8.

On the graph, look at the point where y = 8, on the y-axis. When y = 8, we have two possible values of x. They are -4, and 9.

Thus:

g(-4) = 8

g(9) = 8.

The possible input values for which g(x) = 8, are x = -4, and x = 9.

8 0
3 years ago
Hayley wanted to play football but, they only had 5 trying out they needed a total of 11 players, how many more do they need?
GaryK [48]
Hello!

To solve this you subtract the needed players by the amount of players they have

11 - 5 = 6

The answer is 6 players

Hope this helps!
5 0
3 years ago
Read 2 more answers
Please helpppp me ! If the sum of the roots of the equation mx^2 - (6m+1)x+m^3+m^2+4=0 is equal to 7 , what is the product of it
zepelin [54]

Answer:

The product of its roots is 6.

Step-by-step explanation:

Let m\cdot x^{2}-(6\cdot m +1)\cdot x+(m^{3}+m^{2}+4) = 0, all roots are calculated by Quadratic Formula:

r_{1} = \frac{6\cdot m +1 + \sqrt{(6\cdot m + 1)^{2}-4\cdot m\cdot (m^{3}+m^{2}+4)}}{2\cdot m} (1)

r_{2} = \frac{6\cdot m +1 - \sqrt{(6\cdot m + 1)^{2}-4\cdot m\cdot (m^{3}+m^{2}+4)}}{2\cdot m} (2)

According to statement, we know that:

r_{1}+r_{2} = 7 (3)

By applying (1) and (2) in (3), we have the following expression:

\frac{6\cdot m +1}{m} = 7

6\cdot m + 1 = 7\cdot m

m = 1

If we know that m = 1, then the roots of the polynomial are, respectively:

x^{2}-7\cdot x +6 = 0

r_{1} = 6

r_{2} = 1

And the product of the roots is:

r_{1}\cdot r_{2} = 6

The product of its roots is 6.

7 0
3 years ago
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