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3 years ago

Simplify Sqrt 3 ( sqrt 6 + sqrt 15) Pls explain how u did it!

Mathematics

1 answer:

frozen [14]3 years ago

8 0

Answer:

$= 3 (\sqrt{2} +\sqrt{5})$

Step-by-step explanation:

$\sqrt{3} (\sqrt{6}*\sqrt{15} )$

When you have to simplify an expression, always try to find a common number, even if it isnt the solution to a problem is always a good strategy.

Here the 3 numbers are multiple of 3. So your first idea should be to do something with sqrt 3

$\\ \sqrt{3} (\sqrt{2}\sqrt{3} +\sqrt{5} \sqrt{3} )\\= \sqrt{3} ((\sqrt{2} +\sqrt{5}) \sqrt{3} )\\= \sqrt{3} (\sqrt{3}) (\sqrt{2} +\sqrt{5}) \)\\= 3 (\sqrt{2} +\sqrt{5})$

In this case it works, sometimes it doesnt, but its always a good start point

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Rachel's learning to play the violin Monday through Friday she practices 45 minutes on each day on Saturday and Sundays he broug

I am Lyosha [343]

Rachel spends 6 hours 45 minutes a week trying to learn to play the violin.

Step-by-step explanation:

Step 1; Rachel learns for 45 minutes a day from Monday through Friday and in the weekend she learns to play the violin for one and a half hours. So she learns for the following periods of time

Monday - 45 minutes

Tuesday - 45 minutes

Wednesday - 45 minutes

Thursday - 45 minutes

Friday - 45 minutes

Saturday - 90 minutes (60 × 1.5 hours)

Sunday - 90 minutes (60 × 1.5 hours)

Step 2; To determine how much time she practices in a week we just add the individual times she plays on each day.

Total time practices in a week = 45 + 45 + 45 + 45 + 45 + 90 + 90 = 405 minutes = 6 hours 45 minutes.

5 0

2 years ago

I need help with these three

Ludmilka [50]

A. The relationship of <7 and <8 are that they are vertical angles, and are congruent.

B. Since vertical angles are congruent, you can form an equation where the two measurements equal each other.

C. 5y-29=3y+19 then plug y into your equation: 5*24-29=91
2y=48 and so: <7 = 180-91=89 (and since <8 is congruent)
y=24 <8 also equals 89

Your second problem:
complementary are two angles that add up to 90 degrees.
<B=x, <A=2x
2x+x=90
3x=90
x=30 so: <B=30 degrees, <A=60 degrees

Your third problem:
1. Since A and B are parallel, angle 3x+7 and angle 4x+5 are same-sided exterior angles. That means that they both add up to 180 degrees. So if you should add the two and make it equal 180
2. 3x+7+4x+5=180
7x+12=180
7x=168
x=24
3. <6 is a corresponding angle with angle 3x+7, meaning that they are congruent. So plug x into 3x+7: 3*24+7=79 and since <6 is congruent to 3x+7, <6=79 degrees

6 0

3 years ago

Read 2 more answers

Solve x

d1i1m1o1n [39]

Step-by-step explanation:

$x^{2} - 4x - 7 = 0$

First, let's move the $7$ to the right-hand side so we can determine what constant we'll need on the left-hand side to complete the square:

$x^{2} - 4x = 7$

From here, since the coefficient of the $x$ term is $-4$ , we know the square will be $(x - 2)$ (since $-2$ it's half of $-4$ ).

To complete this square, we will need to add $(-2)^{2}$ to both sides of the equation:

$x^{2} - 4x + (-2)^2 = 7 + ^{-2}$

$x^{2} - 4x + 4 = 7 + 4$

$(x - 2)^{2} = 11$

Now we can take the square root of both sides to figure out the solutions to $x$ :

$x - 2 = \pm \sqrt{11}$

$x = 2 \pm \sqrt{11}$

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3 years ago

i have to write equations in standard form using integer coefficients for A,B, and, C Example: y= -8/15x + 1/20

uysha [10]

Answer:

Step-by-step explanation:

5 0

3 years ago

The magnitude, M, of an earthquake is defined to be M = log StartFraction I Over S EndFraction, where I is the intensity of the

uranmaximum [27]

The equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake is $\rm M = log\left ( \dfrac{10S}{S}\right )$ .

Given

The magnitude, M, of an earthquake is defined to be M = log StartFraction I Over S EndFraction, where I is the intensity of the earthquake (measured by the amplitude of the seismograph wave) and S is the intensity of a "standard" earthquake, which is barely detectable.

<h3>The magnitude of an earthquake</h3>

The magnitude of an earthquake is a measure of the energy it releases.

For an earthquake with 1,000 times more intense than a standard earthquake.

The equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake is;

$\rm M =log \dfrac{I}{S}\\\\M = log \dfrac{10s}{s}\\\\M=log 10\\\\M =1$

Hence, the equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake is $\rm M = log\left ( \dfrac{10S}{S}\right )$ .

To know more about the magnitude of earthquakes click the link given below.

brainly.com/question/1337665

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2 years ago