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Levart [38]
3 years ago
15

The volume of this rectangle prism=____ft3.

Mathematics
1 answer:
serious [3.7K]3 years ago
8 0

Answer:

18

Step-by-step explanation:

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Which of the following statements contain a variable? Check all that apply.
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the answer is D

Step-by-step explanation:

this is because the number is unknown so  you have to put a variable

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Which expression is equivalent to this quotient?
Ne4ueva [31]

Answer:    B. \: \: \: \dfrac{5}{x+5}

Step-by-step explanation:

\dfrac{\dfrac{1}{x+5} }{\dfrac{x+3}{5x+15} } =\dfrac{1}{x+5} \times \dfrac{5x+15}{x+3}=\dfrac{1}{x+5} \times \dfrac{5(x+3)}{x+3}=\dfrac{1}{x+5} \times 5 = \dfrac{5}{x+5}

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2 years ago
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3 years ago
I need help answer question In image.
Viktor [21]
In a fraction, the number below the line (called the denominator) represent the whole. In this problem '8' is in the denominator and represents the 8 slices of pizza there were to start with

Answer=8 slices

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Solve step by step solution then only i can do it plxx ​
Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So \triangle ABC and \triangle ABD Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
  • First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

  • We need to find base=b

According to Pythagoras thereon

{\boxed{\sf b^2=h^2-p^2}}

  • Substitutethe values

\longrightarrow\sf b^2=10^2-p^2

\longrightarrow\sf b={\sqrt {10^2-8^2}}

\longrightarrow\sf b={\sqrt{100-64}}

\longrightarrow\bf b={\sqrt {36}}

\longrightarrow\sf b=6

\therefore\overline{BC}=6cm

  • BD=BC+CD

\longrightarrowBD=9+6

\longrightarrowBD=15cm

  • Now in \triangle ABD

Perpendicular=p=8cm

Base =b=15cm

  • We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

{\boxed {\sf h^2=p^2+b^2}}

  • Substitute the values

\longrightarrow\sf h^2=8^2+15^2

\longrightarrow\sf h={\sqrt {8^2+15^2}}

\longrightarrow\sf h={\sqrt {64+225}}

\longrightarrow\sf h={\sqrt {289}}

\longrightarrow\sf h=17cm

\therefore{\underline{\boxed{\bf x=17cm}}}

3 0
3 years ago
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