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bonufazy [111]
2 years ago
14

A man runs the London marathon at an average speed of 8mph the route is 26 miles what was his time in hours and minutes

Mathematics
1 answer:
user100 [1]2 years ago
4 0

Answer:

the only thing you need to do is to divide the speed with the distance

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Find the value of 7v-10 given that -11v-7=4. Simplify your answer as much as possible.
densk [106]

First thing to do is solve the given equation for v

-11v-7 = 4

-11v = 4+7

-11v = 11

v = 11/(-11)

v = -1

Once we know this, we can use it to compute the following

7v-10 = 7*(-1) - 10 = -7 - 10 = -17

--------------------------------

Answer: -17

4 0
2 years ago
A travel agent currently has 80 people signed up for a tour. The price of a ticket is $5000 per person. The agency has chartered
Nikolay [14]
So hmm let's take a peek at the cost first

so, they chartered the plane for 150 folks with a fixed cost of 250,000
now, incidental fees are 300 per person, if we use the quantity "x", for how many folks, then if "x" persons are booked, then incidental fees are 300x

so, more than likely an insurance agency is charging them 300x for coverage

anyway, thus the cost C(x) = 250,000 + 300x

now, the Revenue R(x), is simple is jut price * quantity

well, the price, thus far we know is 5000 for 80 folks, but it can be lowered by 30 to get one more person, thus increasing profits

so... let's see what the price say y(x) is  \bf \begin{array}{ccllll}
quantity(x)&price(y)\\
-----&-----\\
80&5000\\
81&4970\\
82&4940\\
83&4910
\end{array}\\\\
-----------------------------\\\\

\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ 80}}\quad ,&{{ 5000}})\quad 
%   (c,d)
&({{ 83}}\quad ,&{{ 4910}})
\end{array}
\\\quad \\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{-90}{3}\implies -30
\\ \quad \\\\
% point-slope intercept
y-{{ 5000}}={{ -30}}(x-{{ 80}})\implies y=-30x+2400+5000\\
\left.\qquad   \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y=-30x+7400

so.. now we know y(x) = -30x+7400

now, Revenue is just price * quantity
the price y(x) is -30x+7400, the quantity is "x"

that simply means R(x) = -30x²+7400x


now, for the profit P(x)

the profit is simple, that is just incoming revenue minus costs, whatever is left, is profit
so P(x) = R(x) - C(x)

P(x) = (7400x - 30x²) - (250,000+300x)

P(x) = -30x² + 7100x - 250,000

now, where does it get maximized? namely, where's the maximum for P(x)?

well \bf \cfrac{dp}{dx}=-60x+7100

and as you can see, if you zero out the derivative, there's only 1 critical point, run a first-derivative test on it, to see if its a maximum
7 0
3 years ago
Write a quadratic equation, in factored form solution are 0,and 6
Salsk061 [2.6K]

Answer: x(x-6)=0

4 0
2 years ago
I’ll give brainiest
ElenaW [278]

Answer:

8.33333cm

Step-by-step explanation:

Using the formula

A=wl

Solving forw

w=A/L

=125/15

≈8.33333cm

8.3cm to the nearest tenth

correct so pls mark brainliest

7 0
2 years ago
Please help meeeeee for points
padilas [110]

Answer:

Karma ig

Step-by-step explanation:

Idek ;-;

7 0
3 years ago
Read 2 more answers
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