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tresset_1 [31]
3 years ago
9

True or False: In order to divide fractions, you must have common denominators.

Mathematics
2 answers:
monitta3 years ago
8 0

Answer:

f

Step-by-step explanation:

Elena L [17]3 years ago
3 0

Answer: falseeeeeee

Step-by-step explanation:

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Lee has 3 children, the oldest is twice as old as the oungest, the middle is 5 years older than the youngest, the sum of the chi
tangare [24]
Oldest = 2x
Middle = x + 5
Youngest = x

2x + x + 5 + x = 57
combine like terms

4x + 5 = 57
subtract 5 from both sides

4x = 52
divide both sides by 4 to isolate x

x = 13

Oldest = 2x = 2(13) = 26
Middle = x + 5 = 13 + 5 = 18
Youngest = x = 13
8 0
3 years ago
Read 2 more answers
D Question 5 5. Given A is between Y and Z and YA = 14x, AZ = 10x and YZ = 12x + 48, find AZ<br>​
Anna007 [38]

Answer:

Step-by-step explanation:

If A is in between Y and Z, then;

YA+AZ = YZ

Given.

YA = 14x,

AZ = 10x and

YZ = 12x + 48

Substitute into the formula

14x+10x = 12x+48

Find x;

24x = 12x+48

24x-12x = 48

12x = 48

x = 48/12

x = 4

Get AZ

AZ = 10x

AZ =10(4)

AZ = 40

3 0
3 years ago
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GalinKa [24]
The answer is (D) ....
6 0
3 years ago
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What is the tangent ratio for
yawa3891 [41]

Answer:

tan T = 3/4

tan U = 4/3

Step-by-step explanation:

The tangent ratio is opposite / adjacent. The ratio will vary for each angle since the perspective of each angle will be different. For example Angle T has an adjacent side of 4 while Angle U has an adjacent side of 3. The tangent ratios for Angles U and T are listed below:

tan T = 3/4

tan U = 4/3

3 0
3 years ago
Read 2 more answers
May someone help me with this question please anyone please
djverab [1.8K]
5;\ 5;\ 5;\ 5;\ 7;\ 9\\\\\overline{x}=\dfrac{5+5+5+5+7+9}{6}=\dfrac{36}{6}=6\\\\\delta^2=\dfrac{(x_1-\overline{x})^2+(x_2-\overline{x})^2+(x_3-\overline{x})^2+...+(x_n-\overline{x})^2}{n}\\\\\delta^2=\dfrac{(5-6)^2+(5-6)^2+(5-6)^2+(5-6)^2+}{6}
\dfrac{+(7-6)^2+(9-6)^2}{6}\\\\\delta^2=\dfrac{(-1)^2+(-1)^2+(-1)^2+(-1)^2+1^2+3^2}{6}=\dfrac{14}{6}=\dfrac{7}{3}

standard\ deviation:\\\\\sqrt{\delta^2}=\sqrt{\dfrac{7}{3}}=\dfrac{\sqrt7}{\sqrt3}=\dfrac{\sqrt7\cdot\sqrt3}{\sqrt3\cdot\sqrt3}=\boxed{\dfrac{\sqrt{21}}{3}}\approx\boxed{1.53}
4 0
3 years ago
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