Can you help me out with this question 5 pls

True [87]

Answer:

Step-by-step explanation:

Remark

We really should have 1 more term in the sequence. There could be a lot of things that determine what the sequence is. I'm going to say that each term is multiplied by 3

Givens

a1 = 1

r = 3

Formula

tn = a1 * 3^(n-1)

t100 = 1 * 3^(100 - 1)

t_100 = 3^99

t_100 = 1.72 * 10^47

This really is a scientific calculator problem. If you don't own such a thing, but you have windows 10 on your computer, go to the calculator. Go to the scientific calculator and put in these key strokes.

3

x^y

99

=

This is what you get

1.7179250691067044367882037658854e+47

Naturally, I rounded it a bit.

4 0

2 years ago

I need to finish this by tmr morning or my parents is gettin called lol

Anit [1.1K]

18.84

Step-by-step explanation:

divide 12 by 2 which is 6 then times that by 3.14

8 0

3 years ago

Please help me with this

MA_775_DIABLO [31]

Answer:

13.7 cm²

Step-by-step explanation:

area of yellow region = area of square - area of 4 quarter circles

area of square = 8² = 64

area of 4 congruent quarter circles = area of circle

area of circle with radius = 4

A = π × 4² = 16π

yellow region = 64 - 16π ≈ 13.7 cm²

3 0

2 years ago

a bag contains eleven counters. five are white. a counter is taken out the bag and is not replaced. a second counter is taken ou

Fed [463]

Answer:

$\displaystyle P(A)=\frac{6}{11}$

Step-by-step explanation:

<u>Probabilities</u>

The question describes an event where two counters are taken out of a bag that originally contains 11 counters, 5 of which are white.

Let's call W to the event of picking a white counter in any of the two extractions, and N when the counter is not white. The sample space of the random experience is

$\Omega=\{WW,WN,NW,NN\}$

We are required to compute the probability that only one of the counters is white. It means that the favorable options are

$A=\{WN,NW\}$

Let's calculate both probabilities separately. At first, there are 11 counters, and 5 of them are white. Thus the probability of picking a white counter is

$\displaystyle \frac{5}{11}$