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avanturin [10]
3 years ago
6

Alldlyziny Work Tor Errors

Mathematics
2 answers:
stiks02 [169]3 years ago
8 0

Answer: The correct answer is (B)

Step-by-step explanation: No. Ari should have written the percent ratio as 5/100

choli [55]3 years ago
5 0

Answer:

The correct answer to this fancy little dinner party problem would be "B"

Step-by-step explanation: Well I did take the quiz and passed it, No. Ari should have written the percent ratio as 5/100. Aha. There we go. Hope this all helped! Thanks and I hope YOU have a great day/night | morning/evening!

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2 years ago
The half-life of radium-226 is 1600 years. Suppose we have a 27-mg sample.
slega [8]

A function m(t)= m₀e^(-rt) that models the mass remaining after t years is; m(t) = 27e^(-0.00043t)

The amount of sample that will remain after 4000 years is; 4.8357 mg

The number of years that it will take for only 17 mg of the sample to remain is;  1076 years

<h3>How to solve exponential decay function?</h3>

A) Using the model for radioactive decay;

m(t)= m₀e^(-rt)

where;

m₀ is initial mass

r is rate of growth

t is time

Thus, we are given;

m₀ = 27 mg

r = (In 2)/1600 = -0.00043 which shows a decrease by 0.00043

and so we have;

m(t) = 27e^(-0.00043t)

c) The amount that will remain after 4000 years is;

m(4000) = 27e^(-0.00043 * 4000)

m(4000) = 27 * 0.1791

m(4000) = 4.8357 mg

d) For 17 mg to remain;

17 = 27e^(-0.00043 * t)

17/27 = e^(-0.00043 * t)

In(17/27) = -0.00043 * t

-0.4626/-0.00043 = t

t = 1076 years

Read more about Exponential decay function at; brainly.com/question/27822382

#SPJ1

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1 year ago
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