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avanturin [10]
3 years ago
6

Alldlyziny Work Tor Errors

Mathematics
2 answers:
stiks02 [169]3 years ago
8 0

Answer: The correct answer is (B)

Step-by-step explanation: No. Ari should have written the percent ratio as 5/100

choli [55]3 years ago
5 0

Answer:

The correct answer to this fancy little dinner party problem would be "B"

Step-by-step explanation: Well I did take the quiz and passed it, No. Ari should have written the percent ratio as 5/100. Aha. There we go. Hope this all helped! Thanks and I hope YOU have a great day/night | morning/evening!

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Jade solved the following equation:
sergey [27]

step 1 has incorrect justification

4 0
3 years ago
Which of the following ratios are equivalent ratios to 12:14?
sweet [91]

Answer:

a and c

Step-by-step explanation:

a: when you divide 12:14 by 2 itll give you half of each number. that equals 6:7

c: when you multiply 12:14 by 2 itll give you twice the amount which is 24:28

3 0
3 years ago
Read 2 more answers
Figure A is a scale image of Figure B, as shown.
Inessa [10]

9514 1404 393

Answer:

  x = 2

Step-by-step explanation:

Using the scale factor, we have ...

  x/8 = 0.25/1

  x = 8(0.25) . . . . multiply by 8

  x = 2

_____

<em>Additional comment</em>

I like to write proportions with the variable in the numerator. That way they are easily solved by a single multiplication. The trick is to get corresponding parts in the same positions. Here, the fractions are written ...

  B/A = smaller part / larger part = x/8 = 0.25/1

5 0
3 years ago
Solve the absolute value equation 2x-4&gt;5
lawyer [7]

Hello.

The answer is: X=9/2

Step 1: Add 4 to both sides.

2x−4+4>5+4

2x>9

Step 2: Divide both sides by 2.

2x/2>9/2

X>9/2

Have a nice day

5 0
3 years ago
Exact value of cos45
Anit [1.1K]

It's a value you should probably memorize:

\cos45^\circ=\dfrac{\sqrt2}2=\dfrac1{\sqrt2}

You can derive it using some trigonometric identities, other known values of cosine, and properties of the cosine function. For example, using the double angle identity for cosine:

\cos^2x=\dfrac{1+\cos2x}2

If x=45^\circ, then

\cos^245^\circ=\dfrac{1+\cos90^\circ}2

and you probably know that \cos90^\circ=0, so

\cos^245^\circ=\dfrac12

When we take the square root, we should take the positive root because \cos x>0 whenever 0^\circ:

\cos45^\circ=+\sqrt{\dfrac12}\implies\cos45^\circ=\dfrac1{\sqrt2}

4 0
3 years ago
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