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Basile [38]
2 years ago
15

find the equation of the axis of symmetry for this equation. f(x) = 6x^2 - 3x + 49. hint: to find the axis of symmetry, use equa

tion: x = -b/2a
Mathematics
1 answer:
love history [14]2 years ago
5 0

Answer:

Without graphing, determine whether the parabola -2(3x + 5)(6 - x) opens up or down and ... Use the shortcut to write the equation for the axis of symmetry and find the ...

Step-by-step explanation:

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Write and solve the equation for the following situation:
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B.) x + (x + 16) = 90

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two trains leaves stations 320miles apart at the same time and travel toward eachother. One train travels at 110 miles per hour
I am Lyosha [343]

x/110 = (320-x)/90

<span> Cross multiply</span>

90x = 35200-110x

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4 0
3 years ago
I’m Really lost if I could get a answer it would be greatly appreciated
Nataly [62]
<h3>Answers:</h3>

f(g(x)) = \sqrt{x^2+5}+5\\\\g(f(x)) = x+30+10\sqrt{x-1}

================================================

Work Shown:

Part 1

f(x) = \sqrt{x-1}+5\\\\f(g(x)) = \sqrt{g(x)-1}+5\\\\f(g(x)) = \sqrt{x^2+6-1}+5\\\\f(g(x)) = \sqrt{x^2+5}+5\\\\

Notice how I replaced every x with g(x) in step 2. Then I plugged in g(x) = x^2+6 and simplified.

------------------

Part 2

g(x) = x^2+6\\\\g(f(x)) = \left(f(x)\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}+5\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}\right)^2+2*5*\sqrt{x-1}+\left(5\right)^2+6\\\\g(f(x)) = x-1+10\sqrt{x-1}+25+6\\\\g(f(x)) = x+30+10\sqrt{x-1}\\\\

In step 4, I used the rule (a+b)^2 = a^2+2ab+b^2

In this case, a = sqrt(x-1) and b = 5.

You could also use the box method as a visual way to expand out \left(\sqrt{x-1}+5\right)^2

6 0
3 years ago
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