A)
i.117
ii.117
b)
i.1170
ii.1170
The expression for the kinetic energy is mass times velocity squared over two
For the first question that gives us 2,25 joules
If the ball is at the given height then it has a further 60 Joules in potential energy.
Answer is D
Solution :
Faulty electrical connects = P(A) = 0.80
Mechanical defects = P(B) = 0.92
Mechanical defects are related to loose keys = P(C/B) = 0.27
Improper assembly = P(D/B) = 0.73
Defective wires = P(E/A) = 0.35
Improper connections = P(F/A) = 0.13
Poorly welded wires = P(G/A) = 0.52
Now, the probability due to loose keys = 0.27 x 0.92 = 0.2484
Improperly connected = 0.13 x 0.80 = 0.1040
Poorly welded wires = 0.52 x 0.80 = 0.4160
So, the probability that a failure is due to improperly connected or poorly welded wires = 0.1040 + 0.4160
= 0.5200
Perimeter: 36
5n + 3 = 36
5 · 6.6 + 3 = 36
N = 6.6
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Perimeter: 36
1/4n + 2 = 36
1/4 · 136 + 2 = 36
N = 136
Hopefully i understood the question correctly :) Hope this helps