Answer:
Step-by-step explanation:
In point-slope form, our equation would be y - 9 = 2(x - 1). Expanding, we get y - 9 = 2x - 2. Solving for y, we obtain the form of the equation as shown in the problem: y = 2x + 7.
So, the numbers that would go in the blanks would be 2 and 7, respectively.
Answer:
x < 7
Step-by-step explanation:
Flip the equation to make it easier: x - 6 < 1
Move 6 to the other side and change sign: x < 1 + 6
Do simple addition: x < 7
Answer:
Yes , function is continuous in [0,2] and is differentiable (0,2) since polynomial function are continuous and differentiable
Step-by-step explanation:
We are given the Function
f(x) =
The two basic hypothesis of the mean valued theorem are
- The function should be continuous in [0,2]
- The function should be differentiable in (1,2)
upon checking the condition stated above on the given function
f(x) is continuous in the interval [0,2] as the functions is quadratic and we can conclude that from its graph
also the f(x) is differentiable in (0,2)
f'(x) = 6x - 2
Now the function satisfies both the conditions
so applying MVT
6x-2 = f(2) - f(0) / 2-0
6x-2 = 9 - 1 /2
6x-2 = 4
6x=6
x=1
so this is the tangent line for this given function.
Answers:
x = 6
y = 6*sqrt(2)
=======================
Explanation:
To find these values, you can use the general template of a 45-45-90 triangle or you can use trig ratios
tan(45) = 1
tan(angle) = opposite/adjacent
tan(45) = x/6
1 = x/6
6*1 = x
x = 6
-------
sin(45) = 1/sqrt(2)
sin(angle) = opposite/hypotenuse
sin(45) = 6/y
1/sqrt(2) = 6/y
1*y = sqrt(2)*6
y = 6*sqrt(2)
The answer is 11 sorry if I’m wrong