In order to have infinitely many solutions with linear equations/functions, the two equations have to be the same;
In accordance, we can say:
(2p + 7q)x = 4x [1]
(p + 8q)y = 5y [2]
2q - p + 1 = 2 [3]
All we have to do is choose two equations and solve them simultaneously (The simplest ones for what I'm doing and hence the ones I'm going to use are [3] and [2]):
Rearrange in terms of p:
p + 8q = 5 [2]
p = 5 - 8q [2]
p + 2 = 2q + 1 [3]
p = 2q - 1 [3]
Now equate rearranged [2] and [3] and solve for q:
5 - 8q = 2q - 1
10q = 6
q = 6/10 = 3/5 = 0.6
Now, substitute q-value into rearranges equations [2] or [3] to get p:
p = 2(3/5) - 1
p = 6/5 - 1
p = 1/5 = 0.2
Answer:
8 with a remainder of 4
step by step explanation:
Answer:
8.2
Step-by-step explanation:
(4.5)^2+(6.9)^2=c^2
20.25+47.61=67.86
sqrt of 67.86= 8.2 (rounded already) :)
<h3>
Answer:</h3>
5+(7+x)
<h3>
Step-by-step explanation:</h3>
Finding an Equivalent Expression
The associative property of addition states that you can move the terms that are inside the parentheses and still have the expression remain true. So, in the answer above, I moved 5 out of the parentheses and x into the parentheses. No matter the value of x the value of the expression will remain the same
Examples and Proof
Another example of the associative property could be (1+6)+3 = 1+(6+3). To prove this statement we can evaluate each side of the expression.
First, let's do (1+6)+3
Next, let's do 1+(6+3)
As you can see both of these expressions are the same, thus proving that the associative property works in this situation.
