HELPP!!! WILL GIVE BRAINLIEST AND 5 STARS!!!

Mathematics

1 answer:

seraphim [82]3 years ago

6 0

Answer:

F=73.74 degrees

Step-by-step explanation:

sin=opposite/hypotenuse

opp=24 hyp=25

sin(F)=24/25 (to find angle have to use inverse sin)

sin-1(24/25)=73.74

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Suppose that $3$ is a factor of $a$, $a$ is a divisor of $12$, and $a$ is positive. What is the number of possible values of $a$

antiseptic1488 [7]

If $a$ is a divisor of 12, then

$a \in \{-12, -6, -4, -3, -2, -1, 1, 2, 3, 4, 6, 12\}$

If 3 is a factor (i.e. divisor) of $a$ , then $a$ can only be one of the elements of this set that are multiples of 3, so

$a \in \{-12, -6, -3, 3, 6, 12\}$

But $a$ is positive, so there are 3 possible values $a$ can have.

8 0

1 year ago

Suppose that 35 people are divided in a random manner into two teams in such a way that one team contains 10 people and the othe

Effectus [21]

Answer:

0.5798 or 57.98%

Step-by-step explanation:

The total number of ways to form the two teams is the combination of choosing 10 people out of 35 (₃₅C₁₀). The number of possibilities that A and B are both on the 10-people team is given by the combination of choosing 8 people (since two are fixed) out of 33 (₃₃C₈).The number of possibilities that A and B are both on the 25-people team is given by the combination of choosing 10 people out of 33 (₃₃C₈).

Therefore, the probability that two particular people A and B will be on the same team is:

$P = \frac{_{33}C_8+_{33}C_{10}}{_{35}C_{10}} \\\\P=\frac{\frac{33!}{(33-8)!8!}+\frac{33!}{(33-10)!10!} }{\frac{35!}{(35-10)!10!}} \\\\P=\frac{69}{119} = 0.5798$