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Keith_Richards [23]
3 years ago
12

Which inequality represents the solution set {9, 10, 11...}?

Mathematics
1 answer:
Over [174]3 years ago
8 0

Answer:

x is greater than or equal to nine(since it starts at and includes nine) and belongs to natural numbers(counting numbers)

Step-by-step explanation:

I think there are multiple answers to this but I will just give mine

x is greater than or equal to nine(since it starts at and includes nine) and belongs to natural numbers(counting numbers)

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F(x) = 3x^3 -2x^2 - 19x -6
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The arch beneath a bridge is​ semi-elliptical, a​ one-way roadway passes under the arch. The width of the roadway is 38 feet and
forsale [732]

Answer:

Only truck 1 can pass under the bridge.

Step-by-step explanation:

So, first of all, we must do a drawing of what the situation looks like (see attached picture).

Next, we can take the general equation of an ellipse that is centered at the origin, which is the following:

\frac{x^2}{a^2}+\frac{y^2}{b^2}

where:

a= wider side of the ellipse

b= shorter side of the ellipse

in this case:

a=\frac{38}{2}=19ft

and

b=12ft

so we can go ahead and plug this data into the ellipse formula:

\frac{x^2}{(19)^2}+\frac{y^2}{(12)^2}

and we can simplify the equation, so we get:

\frac{x^2}{361}+\frac{y^2}{144}

So, we need to know if either truk will pass under the bridge, so we will match the center of the bridge with the center of each truck and see if the height of the bridge is enough for either to pass.

in order to do this let's solve the equation for y:

\frac{y^{2}}{144}=1-\frac{x^{2}}{361}

y^{2}=144(1-\frac{x^{2}}{361})

we can add everything inside parenthesis so we get:

y^{2}=144(\frac{361-x^{2}}{361})

and take the square root on both sides, so we get:

y=\sqrt{144(\frac{361-x^{2}}{361})}

and we can simplify this so we get:

y=\frac{12}{19}\sqrt{361-x^{2}}

and now we can evaluate this equation for x=4 (half the width of the trucks) so:

y=\frac{12}{19}\sqrt{361-(8)^{2}}

y=11.73ft

this means that for the trucks to pass under the bridge they must have a maximum height of 11.73ft, therefore only truck 1 is able to pass under the bridge since truck 2 is too high.

5 0
3 years ago
Help me out :O What is the volume of three cubes, each with a side length of fraction 1 over 3 foot? V = s3, where s is the side
Readme [11.4K]

Answer:

Step-by-step explanation:

s = \frac{1}{3}ft\\

Volume of a cube  =  s³ ft³

Volume of 3 cubes = 3 * s³

                               = 3 * \frac{1}{3} * \frac{1}{3} *\frac{1}{3}\\\\= \frac{1}{3} *\frac{1}{3}\\\\=\frac{1}{3*3}\\\\=\frac{1}{9} ft^{3}

4 0
4 years ago
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