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leonid [27]
3 years ago
13

Pleeaassse help, 80 points:

Mathematics
1 answer:
Ainat [17]3 years ago
4 0
Let p (x) = 5x^3+8x^2-7x-6

using factor theorem,
(x+2) is a factor of p (x) only if p (-2) = 0

p (-2) = 5×-2^3+8×-2^2-7×-2-6
= -40+32+14-6
= -40 + 40
= 0
since remainder = 0
therefore (x+2) is a factor of p (x)

Again,
using factor theorem,
(x+1) is a factor of p (x) only if p (-1) = 0

p (-1) = 5×-1^3+8×-1^2-7×-1-6
= -5 + 8 + 7 - 6
= 3 + 1
= 4
since remainder is not equal to 0
therefore (x+1) is not a factor of p (x)

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x+y=11 \\
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\hbox{substitute the second equation by -1} \\ \\
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Direction: Opens Up

Vertex:

(

4

,

−

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)

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Focus:

(

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−

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(4,-714)

Axis of Symmetry:

x

=

4

x=4

Directrix:

y

=

−

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y=-734

Select a few

x

x values, and plug them into the equation to find the corresponding

y

y values. The

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x values should be selected around the vertex.x

y

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4

−

18

5

−

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6

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xy2-143-174-185-176-14

Graph the parabola using its properties and the selected points.

Direction: Opens Up

Vertex:

(

4

,

−

18

)

(4,-18)

Focus:

(

4

,

−

71

4

)

(4,-714)

Axis of Symmetry:

x

=

4

x=4

Directrix:

y

=

−

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x

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3

−

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4

−

18

5

−

17

6

−

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