Pleeaassse help, 80 points:
       
      
                
     
    
    
    
    
    1 answer:
            
              
              
                
                
Let p (x) = 5x^3+8x^2-7x-6
using factor theorem,
(x+2) is a factor of p (x) only if p (-2) = 0
p (-2) = 5×-2^3+8×-2^2-7×-2-6
= -40+32+14-6
= -40 + 40
= 0
since remainder = 0
therefore (x+2) is a factor of p (x)
Again,
using factor theorem,
(x+1) is a factor of p (x) only if p (-1) = 0
p (-1) = 5×-1^3+8×-1^2-7×-1-6
= -5 + 8 + 7 - 6
= 3 + 1
= 4
since remainder is not equal to 0
therefore (x+1) is not a factor of p (x)
                                
             
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the answer is 5
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2x/5 - 9 = -7
2x/5      = -7 + 9
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2x         = 2 * 5
2x         = 10
x            = 10/2
x            = 5
 
        
                    
             
        
        
        
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 or 4
 or 4
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<span>b. 4+12÷2=4+6=10
 c. (20–5)•3=15•3=45</span>
        
             
        
        
        
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