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harkovskaia [24]
2 years ago
15

Samuel bought an 8-ounce bag of lettuce and a 1-pound bag of carrots. what is the total weight of the lettuce and carrots in oun

ces?
Mathematics
1 answer:
Masja [62]2 years ago
8 0

Answer:

the answer is 10z

Step-by-step explanation:

7+1=8

8+2=10

10z

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On a graph the y axis goes by 200’s while the x axis goes by 10’s, I’m given the first equation y=8x+400 and told the slope is 8
svp [43]
Don’t trust those links it doesn’t work at all
3 0
2 years ago
2. Suppose that you are looking for a student at your college who lives within five miles of you. You know that 55% of the 25,00
svlad2 [7]

Using the binomial distribution, it is found that:

a) There is a 0.0501 = 5.01% probability that you need to contact four people.

b) You expect to contact 1.82 students until you find one who lives within five miles of you.

c) The standard deviation is of 1.22 students.

d) There is a 0.3369 = 33.69% probability that 3 of them live within five miles of you.

e) It is expected that 2.75 students live within five miles of you.

For each student, there are only two possible outcomes. Either they live within 5 miles of you, or they do not. The probability of a student living within 5 miles of you is independent of any other student, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 55% of the students live within five miles of you, thus p = 0.55.

Item a:

This probability is P(X = 0) when n = 3(none of the first three living within five miles of you) multiplied by 0.55(the fourth does live within five miles), hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.55)^{0}.(0.45)^{3} = 0.091125

p = 0.091125(0.55) = 0.0501

0.0501 = 5.01% probability that you need to contact four people.

Item b:

The expected number of trials in the binomial distribution until q successes is given by:

E = \frac{q}{p}

In this problem, p = 0.55, and 1 trial, thus q = 1, hence:

E = \frac{1}{0.55} = 1.82

You expect to contact 1.82 students until you find one who lives within five miles of you.

Item c:

The standard deviation of the number of trials until q successes are found is given by:

S = \frac{\sqrt{q(1 - p)}}{p}

Hence, since q = 1, p = 0.55:

S = \frac{\sqrt{0.45}}{0.55} = 1.22

The standard deviation is of 1.22 students.

Item d:

This probability is P(X = 3) when n = 5, hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{5,3}.(0.55)^{3}.(0.45)^{2} = 0.3369

There is a 0.3369 = 33.69% probability that 3 of them live within five miles of you.

Item e:

The expected value of the binomial distribution is:

E(X) = np

Hence, since n = 5, p = 0.55:

E(X) = 5(0.55) = 2,75

It is expected that 2.75 students live within five miles of you.

A similar problem is given at brainly.com/question/25343741

7 0
3 years ago
Find the missing value so that the line passing through the points has the given slope.
Dominik [7]

Answer:

y = 2

Step-by-step explanation:

use slope formula:

(4 - y) / (3 - 10) = -2/7

4-y / -7 = -2 /7

cross-multiply:

7(4 - y) = (-7)(-2)

28 - 7y = 14

-7y = -14

y = 2

4 0
2 years ago
Leonora is factoring a trinomial. The factors of the trinomial are shown on the model.
Temka [501]

Answer:

D

Step-by-step explanation: just trust me

8 0
3 years ago
The blue shape is a dilation of the black shape. What is the scale factor of the dilation?
BabaBlast [244]

Answer:

scale factor = 4

Step-by-step explanation:

The ratio of corresponding sides, blue shape to black shape.

The corresponding widths are 1 and 4 , then

scale factor = \frac{4}{1} = 4

4 0
3 years ago
Read 2 more answers
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