(NEED HELP ASAP) The map is similar to the map from the previous unit. The x-axis runs from -110 to +110. For the y-axis, the va
lues run from -80 to +80. Each tick mark on the axes has the value of 5 m (so each square on the grid represents 10 m). The additional path, Archimedes Alley has been added to the map.
The standard form for one of the three equations is 9x - 20y - 900 = 0.
i) Determine the x- and y-intercepts for the line.
ii) Identify its equivalent equation in slope y-intercept form.
iii) Explain how you chose the equation in slope y-intercept form.
The standard form for one of the three equations is 9x - 20y - 900 = 0.
i) Determine the x- and y-intercepts for the line.
ii) Identify its equivalent equation in slope y-intercept form.
iii) Explain how you chose the equation in slope y-intercept form.
1 answer:
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Answer:
Eli has saved $10
Step-by-step explanation:
Let us use the first letters of their names to represent them.
A for Angela and E for ELi
So, from the first statement, we can write out an equation: E = A + 8, that is, <em>one-third of Angela's savings + $8 will give us Eli's savings</em>
From the second statement, we can write out: E + 10 = (A + 10) + 4 which means that <em>if $10 is added to both their savings, Eli will still have $4 more than Angela.</em>
So, we can solve both equations;
Equation 1: E = A + 8
Equation 2: E + 10 = (A + 10) + 4; which can be rewritten as E + 10 = A + 14
and then E = A + 4
The two equations (in bold), can then be solved simultaneously.
Let us carry out this operation to <u>eliminate the E:</u> Subtract equation 1 from equation 2, so that;
A + 4 - ( A + 8) = E - E
A - 4 = 0
A = 4
A = 4 × = 6
So, if A is 6, and E = A + 4 (from equation 2, that means that E = 6 + 4 = 10
So, Eli has saved $10, while Angela has saved $6.
If we check what was said in the question about their savings, which is what we have represented using the equations, the answers can be confirmed.
x = 2
<em>right</em><em> </em><em>option</em><em> </em><em>is</em><em> </em>(E).
Step-by-step explanation:
f(x) = x³ - 3x² + 12 in interval [-2, 4]
{taking f'(x) by doing derivative of f(x)}
f'(x) = 3x² - 6x
.•. f'(x) = 0
0 = 3x² - 6x
0 = 3x(x - 2)
0 = x - 2
x = 2