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Kobotan [32]
3 years ago
12

(NEED HELP ASAP) The map is similar to the map from the previous unit. The x-axis runs from -110 to +110. For the y-axis, the va

lues run from -80 to +80. Each tick mark on the axes has the value of 5 m (so each square on the grid represents 10 m). The additional path, Archimedes Alley has been added to the map.
The standard form for one of the three equations is 9x - 20y - 900 = 0.
i) Determine the x- and y-intercepts for the line.
ii) Identify its equivalent equation in slope y-intercept form.
iii) Explain how you chose the equation in slope y-intercept form.

Mathematics
1 answer:
sergeinik [125]3 years ago
3 0
First oneeeewweemdjdjjdjdjjdid
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Number one is parallel


4 0
3 years ago
Help me solve this please
damaskus [11]

1) A quadratic will have no real roots when its discriminant is negative


0 = ax^2 + bx + c = x^2 + 2k x + (4k-3)


d = b^2 - 4ac =  (2k)^2 - 4(1)(4k-3) = 4k^2 - 16k + 12 < 0


Dividing by 4,


k^2 - 4 k + 3 < 0 \quad\checkmark


We have a positive coefficient on k^2 so this parabola is a CUP (concave up positive) so has a minimum at the vertex. If the vertex y value is less than zero, the inequality will be true in the range between the zeros.


(k-3)(k-1)


That's true for


1 < k < 3


2) We look for the meet of the line and the parabola:


2x + k + 2 = 2x^2 + (k+2)x + 8


0 = 2x^2 + kx + (6-k)


For two intersections we need a positive discriminant:


k^2 - 4(6-k)(2) > 0


k^2 + 8k - 48 > 0


(k+12)(k-4) > 0


That's means two negative or two positive, so


k < 12 or k > 4


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3 years ago
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Gwar [14]

Answer:

I know that 4 is 35

Step-by-step explanation:

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