Answer:
The distance from A to B is 736.2 to the nearest tenth foot
Step-by-step explanation:
In ΔCAB
∵ m∠CAD = 30° ⇒ exterior angle of Δ at vertex A
∴ m∠CAD = m∠ACB + m∠ABC
∵ m∠ABC = 20°
∴ m∠ACB = 30° - 20° = 10°
We will use the sin rule to find the distance AB
∵ 
∴ 
≅ 736.2 to the nearest tenth foot
The first one is 32m^15n^10
The second one is:
(h^12/h^4)^5
(h^6/h)^5
h^30/h^5
h^25/h
Hope this helps :)
B cause you take y times it by the circumference
a) Choose Z since the σ is smallest . The smaller the σ the higher the consistency. Also we can see that the fewest day the student attendance is higher than other while the highest day is the same with others. (L = 130 ,H = 180)
b) Choose W since mean in W is the highest.
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Answer:
864ft^3
Step-by-step explanation:
Divide the diameter by 2 to get the radius
12 / 2 = 6
Then solve the volume equation using 3 for pi.
4/3 * 3 * 6^3
4 * 6^3
4 * 216 = 864
