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3 years ago

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Negative 1 over 2 x + 3 = –x + 7

1 answer:

MAVERICK [17]3 years ago

4 0

-1/2x+3=-x+7
Multiply throughout by 2x
-1+6x=-2x^2+14x
2x^2-8x-1=0

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Intersection point of Y=logx and y=1/2log(x+1)

GalinKa [24]

Answer:

The intersection is $(\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2})$ .

The Problem:

What is the intersection point of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ ?

Step-by-step explanation:

To find the intersection of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ , we will need to find when they have a common point; when their $x$ and $y$ are the same.

Let's start with setting the $y$ 's equal to find those $x$ 's for which the $y$ 's are the same.

$\log(x)=\frac{1}{2}\log(x+1)$

By power rule:

$\log(x)=\log((x+1)^\frac{1}{2})$

Since $\log(u)=\log(v)$ implies $u=v$ :

$x=(x+1)^\frac{1}{2}$

Squaring both sides to get rid of the fraction exponent:

$x^2=x+1$

This is a quadratic equation.

Subtract $(x+1)$ on both sides:

$x^2-(x+1)=0$

$x^2-x-1=0$

Comparing this to $ax^2+bx+c=0$ we see the following:

$a=1$

$b=-1$

$c=-1$

Let's plug them into the quadratic formula:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{1 \pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}$

$x=\frac{1 \pm \sqrt{1+4}}{2}$

$x=\frac{1 \pm \sqrt{5}}{2}$

So we have the solutions to the quadratic equation are:

$x=\frac{1+\sqrt{5}}{2}$ or $x=\frac{1-\sqrt{5}}{2}$ .

The second solution definitely gives at least one of the logarithm equation problems.

Example: $\log(x)$ has problems when $x \le 0$ and so the second solution is a problem.

So the $x$ where the equations intersect is at $x=\frac{1+\sqrt{5}}{2}$ .

Let's find the $y$ -coordinate.

You may use either equation.

I choose $y=\log(x)$ .

$y=\log(\frac{1+\sqrt{5}}{2})$

The intersection is $(\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2})$ .

6 0

2 years ago

Find KL.<br> K<br> X-1<br> L<br> 12<br> M

Aneli [31]

Answer:

KL = 9

Step-by-step explanation:

(7 + x - 1)(x - 1) = 12²

(x + 6)(x - 1) = 144

x² -x + 6x - 6 = 144

reduce:

x² + 5x -150 = 0

(x + 15)(x - 10) = 0

x = -15, x = 10

KL = 10 - 1 = 9

6 0

2 years ago

JT = 2x + 9,<br> CJ = 6x + 4, and<br> CT = 37,<br> Find JT.

Katyanochek1 [597]

Answer:JT=15

Step-by-step explanation:

3 0

3 years ago

If I have 2 quarters 12 dimes and 23 pennies how many more pennies will I need in order to have a toldal of $2.00

umka2103 [35]

Answer:

You will need 7 more pennies.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Please help me 17+2(7+3)-2^2

drek231 [11]

Answer:

t&hhhheeeee awwwwwnnnnssseeerrr is 33

3 0

3 years ago