Answer:
Four unique planes
Step-by-step explanation:
Given that the points are non co-planar, triangular planes can be formed by the joining of three points
The points will therefore appear to be at the corners of a triangular pyramid or tetrahedron such that together the four points will form a three dimensional figure bounded by triangular planes
The number of triangular planes that can therefore be formed is given by the combination of four objects taking three at a time as follows;
₄C₃ = 4!/(3!×(4-3)! = 4
Which gives four possible unique planes.
We can solve this by using the formula:
(x, y) (x + a, y + b) = (5,-4) (-2,1)
So, plugging in the values and solving for a and b,
5 + a = -2
a = -8
-4 + b = 1
b = 5
Therefore, the translation is
(x,y) (x - 8, y +5)
I'm going to go right ahead and assume that we're talking about a linear equation.
The linear equation passing through the points given is y=3x+4, since it satisfies both of the points given.
44
Assuming JM and LN are parallel, KMJ=MKN. MKN is part of a triangle where the other two values are defined (48 and 88). By subtracting these values from 180, we find the value of MKN is 44, which therefore is also the value of KMJ.
Answer:
First Problem:
1/2 * -2 2/5 = 1/2 * -12/5 = -12/10
Simplify -12/10 into -6/5
Step-by-step explanation:
