Question

Solve the quadratic equation and give both solutions. 14x^2 − 29x − 15 = 0

Answer 1

Answer:

Step-by-step explanation:

$x_{1,\:2}=\frac{-\left(-29\right)\pm \sqrt{\left(-29\right)^2-4\cdot \:14\left(-15\right)}}{2\cdot \:14}$     so    $x=\frac{5}{2}$     $x=-\frac{3}{7}$